Question

我正在玩Android和iOS的实验性Bluetooth LE程序，现在我在iOS端发送的Android端过滤信标广告上遇到了一些麻烦。 Android有一个功能，可以通过UUID使用掩码过滤广告（我需要这个，因为我试图从特定值开始获取UUID）但我无法使其工作。这是我正在尝试的内容：

private void freshen() {
    // kill current scanner
    if (mLEScanner != null)
        mLEScanner.stopScan(mScanCallback);

    // set new one to be a match scanner
    ScanSettings settings = new ScanSettings.Builder()
            .setScanMode(ScanSettings.SCAN_MODE_LOW_LATENCY)
            .build();

    List<ScanFilter> filters = new ArrayList<>();

    // create data uuid starting with the value 1
    ParcelUuid data = ParcelUuid.fromString("10000000-0000-0000-0000-000000000000");
    // create a mask to ensure only that value is searched
    ParcelUuid mask = ParcelUuid.fromString("10000000-0000-0000-0000-000000000000");

    // build the filter
    ScanFilter.Builder builder = new ScanFilter.Builder();
    builder.setServiceUuid(data, mask);
    ScanFilter filter = builder.build();

    // add the filter to the scanner
    filters.add(filter);
    mLEScanner.startScan(filters, settings, mScanCallback);
}

产生零结果。即使我将所有掩码值设置为0（这是忽略的数字），它仍然会产生零结果。当我删除过滤器时，会出现以1开头的大量结果。这在当前版本的Android中是否已被破坏？

Answer 1

它不能解决这个问题，但我决定使用DeviceName进行过滤，因为这可以由Android和iOS双方填充。现在我专注于iOS到Android的通信=＆gt;

的iOS：

func centralManager(_: CBCentralManager, didDiscover peripheral: CBPeripheral, advertisementData: [String : Any], rssi: NSNumber){

    delegate?.didDiscoverPeripheral(peripheral)
    let splitUp : [String] = "\(advertisementData)".components(separatedBy: "\n")
    if (splitUp.count > 1)
    {
        var chop = splitUp[1]
        let counter = chop.characters.count - 2
        chop = chop[0..<counter]
        let chopSplit : [String] = "\(chop)".components(separatedBy: "\"")

        if !(chopSplit.count > 1 && chopSplit[1] == "Device Information" && !sending)
        {
            let hexString = chop[4..<7] + chop[12..<19] + chop[21..<26]
            let hexArray = [hexString[0..<1], hexString[2..<3], hexString[4..<5], hexString[6..<7], hexString[8..<9], hexString[10..<11], hexString[12..<13], hexString[14..<15], hexString[16..<17]]
            let charArray = hexArray.map { Character(hexToScalar(char: $0)) }
            let string = String(charArray) as String
            if (string == "GoTcHa" + stringify(number: writing))
            {
                writing += 1
                let messageUUID = StringToUUID(hex: String(writing) + "hello" + String(writing))
                peripheralManager.stopAdvertising()
                let name = String(writing) as NSString
                peripheralManager.startAdvertising([CBAdvertisementDataServiceUUIDsKey: [CBUUID(string: messageUUID)], CBAdvertisementDataLocalNameKey: name])
            }
        }
    }
}

func StringToUUID(hex: String) -> String
{
    var rev = String(hex.characters.reversed())
    let hexData: NSData! = rev.data(using: String.Encoding.utf8, allowLossyConversion: false) as NSData!
    rev = hexData.toHexString()
    while(rev.characters.count < 31) {
        rev = "0" + rev;
    }
    rev = String(writing % 10) + rev[0..<30]
    let finalString = rev[0..<7] + "-" + rev[8..<11] + "-" + rev[12..<15] + "-" + rev[16..<19] + "-" + rev[20..<31]
    return finalString
}

更重要的是Android扫描方法，它现在通过始终通过DeviceName查找下一条消息来忽略来自iOS的重复消息：

private void freshen() {
    if (mLEScanner != null)
        mLEScanner.stopScan(mScanCallback);
    ScanSettings settings = new ScanSettings.Builder()
            .setScanMode(ScanSettings.SCAN_MODE_LOW_LATENCY)
            .setNumOfMatches(ScanSettings.MATCH_NUM_ONE_ADVERTISEMENT)
            .build();

    List<ScanFilter> filters = new ArrayList<>();

    ScanFilter filter = new ScanFilter.Builder()
            .setDeviceName("" + (reading % 10))
            .build();

    filters.add(filter);

    mLEScanner.startScan(filters, settings, mScanCallback);
}

我需要让iOS方面现在更好地过滤Android的响应，但它在Android接收方面有效。

Android蓝牙LE蒙面UUID过滤器

1 个答案: