Question

我试图让作者满足EXISTS条件下的两个条件。但是，当子查询实际工作时，我会继续获取作者表中的所有条目。谁能告诉我我的查询究竟出了什么问题？我目前正在计算参赛人数。

SELECT COUNT(*) 
FROM author
WHERE 
EXISTS (SELECT A.author_id, A.author_name
FROM author AS A 
INNER JOIN author_publication AS AP ON A.author_id = AP.author_id
INNER JOIN publication AS P ON AP.pub_id = P.pub_id
WHERE P.pub_key LIKE '%/pvldb/%'
GROUP BY A.author_id
HAVING COUNT(*)>=10)
AND
EXISTS (SELECT A.author_id, A.author_name
FROM author AS A 
INNER JOIN author_publication AS AP ON A.author_id = AP.author_id
INNER JOIN publication AS P ON AP.pub_id = P.pub_id
WHERE P.pub_key LIKE '%/sigmod/%'
GROUP BY A.author_id
HAVING COUNT(*)>=10)
;

Answer 1

您的子查询与主查询没有任何关系。因此，对于每个记录，您都会问同一个问题：＆＃34;表中是否存在至少十种特定类型的出版物的作者？＆＃34;。每个记录的答案都是相同的，因此您可以获得所有记录。您真正想要问的是：＆＃34;表中是否存在至少十种特定类型的出版物

SELECT COUNT(*) 
FROM author
WHERE EXISTS 
(
  SELECT 1
  FROM author_publication AS AP 
  INNER JOIN publication AS P ON AP.pub_id = P.pub_id
  WHERE AP.author_id = author.author_id
  AND P.pub_key LIKE '%/pvldb/%'
  GROUP BY AP.author_id
  HAVING COUNT(*) >= 10
) 
AND EXISTS 
(
  SELECT 1
  FROM author_publication AS AP 
  INNER JOIN publication AS P ON AP.pub_id = P.pub_id
  WHERE AP.author_id = author.author_id
  AND P.pub_key LIKE '%/sigmod/%'
  GROUP BY AP.author_id
  HAVING COUNT(*) >= 10
);

如果要编写非相关子查询，请改用IN：

SELECT COUNT(*) 
FROM author
WHERE author_id IN 
(
  SELECT AP.author_id
  FROM author_publication AS AP 
  INNER JOIN publication AS P ON AP.pub_id = P.pub_id
  WHERE P.pub_key LIKE '%/pvldb/%'
  GROUP BY AP.author_id
  HAVING COUNT(*) >= 10
) 
AND author_id IN 
(
  SELECT AP.author_id
  FROM author_publication AS AP 
  INNER JOIN publication AS P ON AP.pub_id = P.pub_id
  WHERE P.pub_key LIKE '%/sigmod/%'
  GROUP BY A.author_id
  HAVING COUNT(*) >= 10
);

以下是如何使用单个子查询执行此操作：

SELECT COUNT(*) 
FROM
(
  SELECT AP.author_id
  FROM author_publication AS AP 
  INNER JOIN publication AS P ON AP.pub_id = P.pub_id
  WHERE P.pub_key LIKE '%/pvldb/%' OR P.pub_key LIKE '%/sigmod/%'
  GROUP BY AP.author_id
  HAVING COUNT(CASE WHEN P.pub_key LIKE '%/pvldb/%' THEN 1 END) >= 10
     AND COUNT(CASE WHEN P.pub_key LIKE '%/sigmod/%' THEN 1 END) >= 10
) found_authors;

Answer 2

尝试：

SELECT COUNT(A.author_id)
FROM
  author AS A
    INNER JOIN author_publication AS AP ON A.author_id = AP.author_id
    INNER JOIN publication AS P ON AP.pub_id = P.pub_id
WHERE
  P.pub_key LIKE '%/pvldb/%' OR P.pub_key LIKE '%/sigmod/%'
GROUP BY A.author_id
HAVING COUNT(A.author_id) >= 10;

Answer 3

您只需要将子查询与主查询相关联：

SELECT COUNT(*) 
FROM author as AA
WHERE 
EXISTS (SELECT A.author_id, A.author_name
FROM author AS A 
INNER JOIN author_publication AS AP ON A.author_id = AP.author_id
INNER JOIN publication AS P ON AP.pub_id = P.pub_id
WHERE P.pub_key LIKE '%/pvldb/%'
AND AA.author_id=A.author_id
GROUP BY A.author_id
HAVING COUNT(*)>=10)
AND
EXISTS (SELECT A.author_id, A.author_name
FROM author AS A 
INNER JOIN author_publication AS AP ON A.author_id = AP.author_id
INNER JOIN publication AS P ON AP.pub_id = P.pub_id
WHERE P.pub_key LIKE '%/sigmod/%'
AND AA.author_id=A.author_id
GROUP BY A.author_id
HAVING COUNT(*)>=10)
;

使用EXISTS在MySQL中查询的两个条件

3 个答案: