Question

我在getjson调用中有一个for循环，但循环不起作用......

var woeid = '455827';
    var yql = encodeURIComponent('select * from weather.forecast where woeid = "' + woeid + '"and u="c"')
        $$.getJSON('https://query.yahooapis.com/v1/public/yql?q='+ yql + '&format=json', function (data) {

        var forecast = data.query.results.channel.item.forecast;

        //Forecast
        for(var i=0;i<=forecast.length;i++){
        //Get
        code = data.query.results.channel.item.forecast[i].code;
        data = data.query.results.channel.item.forecast[i].date;
        weekday = data.query.results.channel.item.forecast[i].day;
        max = data.query.results.channel.item.forecast[i].high;
        min = data.query.results.channel.item.forecast[i].low;
        console.log(max);
        }
        });},3000)

循环不起作用，console.log什么都没显示......出了什么问题？

由于

Answer 1

解决：我将我的代码更改为：

而不是

var forecast = data.query.results.channel.item.forecast;
for(var i=0;i<=forecast.length;i++){
        //Get
        code = data.query.results.channel.item.forecast[i].code;
        data = data.query.results.channel.item.forecast[i].date;
        weekday = data.query.results.channel.item.forecast[i].day;
        max = data.query.results.channel.item.forecast[i].high;
        min = data.query.results.channel.item.forecast[i].low;
}

我做了

var forecast = data.query.results.channel.item.forecast;
for(var i=0;i<=forecast.length;i++){
            //Pega      
            code = forecast[i].code;
            data = forecast[i].date;
            weekday = forecast[i].day;
            max = forecast[i].high;
            min = forecast[i].low;
}

虽然我相信第一个代码应该可行，但第二个代码对我来说就像魅力一样

谢谢大家：）

对于getjson中的循环 - Framework7 / Jquery

1 个答案: