我是Laravel的新手,我正在寻找一种使用工厂种植数据透视表的好方法。我不想使用普通的播种机。我会告诉你案件:
我有三个表(用户,技能和 user_skill )。
users user_skill skills
+----------------+ +----------------------+ +-----------------+
| id | name | | user_id | section_id | | id | skills |
+----------------+ +----------------------+ +-----------------+
| 1 | Alex | | | | | 1 | draw |
|----------------| |----------------------| |-----------------|
| 2 | Lucy | | | | | 2 | program |
|----------------| |----------------------| |-----------------|
| 3 | Max | | | | | 3 | social |
|----------------| |----------------------| +-----------------+
| 4 | Sam | | | |
+----------------+ +----------------------+
是否有一种很好的方法可以获取用户表的真实Id
和技能表的真实Id
种子数据透视表?我想随意做,但我不想要与任何id匹配的随机数字。我希望ID与用户和技能匹配。
我不知道如何开始,我正在寻找一个好榜样。也许是这样的?
$factory->defineAs(App\User::class, 'userSkills', function ($faker) {
return [
'user_id' => ..?
'skills_id' => ..?
];
});
答案 0 :(得分:6)
我不认为这是最好的方法,但它对我有用。
$factory->define(App\UserSkill::class, function (Faker\Generator $faker) {
return [
'user_id' => factory(App\User::class)->create()->id,
'skill_id' => factory(App\Skill::class)->create()->id,
];
});
如果您不想仅为数据透视表创建模型,可以手动插入。
DB::table('user_skill')->insert(
[
'user_id' => factory(App\User::class)->create()->id,
'skill_id' => factory(App\Skill::class)->create()->id,
]
);
或者,随机存在的值。
DB::table('user_skill')->insert(
[
'user_id' => User::select('id')->orderByRaw("RAND()")->first()->id,
'skill_id' => Skill::select('id')->orderByRaw("RAND()")->first()->id,
]
);
答案 1 :(得分:2)
我在Laravel测试中遇到了类似的问题,并且以这种方式解决了。
不需要创建新的userSkills模型:
Laravel 5.7版
users user_skill skills
+----------------+ +------------------------------------+ +-----------------+
| id | name | | user_id | section_id | state_skill | | id | skills |
+----------------+ +------------------------------------+ +-----------------+
| 1 | Alex | | | | | | 1 | draw |
|----------------| |----------------------|-------------| |-----------------|
| 2 | Lucy | | | | | | 2 | program |
|----------------| |----------------------|-------------| |-----------------|
| 3 | Max | | | | | | 3 | social |
|----------------| |----------------------|-------------| +-----------------+
| 4 | Sam | | | | |
+----------------+ +----------------------+-------------+
<?php
namespace App;
use Illuminate\Notifications\Notifiable;
use Illuminate\Contracts\Auth\MustVerifyEmail;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Illuminate\Database\Eloquent\SoftDeletes;
class User extends Authenticatable
{
use Notifiable;
use SoftDeletes;
public function skills()
{
return $this->belongsToMany('App\Skill')
->withTimestamps()
->withPivot('state_skill');
}
}
<?php
namespace Tests\Unit;
use Tests\TestCase;
use Illuminate\Foundation\Testing\WithFaker;
use Illuminate\Foundation\Testing\RefreshDatabase;
use Illuminate\Support\Facades\Schema;
class DataBaseTest extends TestCase
{
/**
* @test
*/
public function test_create_user_skill()
{
// Create DataBase
$users = factory(\App\User::class, 1)
->create()
->each(function ($user) {
// Create Models Support
$skill = factory(\App\Skill::class)->create();
// Create Pivot with Parameters
$user->skills()->attach($skill->id,[
'state_skill' => 'ok'
]);
});
// Testing
// ...
$this->assertTrue(true);
}
}
答案 2 :(得分:1)
对于那些正在使用laravel 8.x并正在寻找解决此类问题的人的人;
在laravel 8.x中,您可以使用魔术方法喂食您的枢轴, 例如,如果在用户模型中有一个名为“ userSkills”的belongsToMany关系,则应通过以下方式喂入数据透视表:
User::factory()->hasUserSkills(1, ['skills' => 'draw'])->create();