我正在尝试更改每个第2,第3和第4的背景颜色。
所以基本上我需要它们的顺序是:
绿色,红色,蓝色,黑色。
这是我的小提琴
https://jsfiddle.net/7qkd8jwe/1/
这是我的CSS代码:
.item:nth-child(2n+1) {
background-color:red;
}
.item:nth-child(3n+2) {
background-color:blue;
}
.item:nth-child(4n+4) {
background-color:black;
}
.item{
width:100%;
height:100px;
background-color:green;
margin-bottom:10px;
}
有人可以就此问题提出建议吗?
任何帮助都将不胜感激。
这不是关于在其他问题中建议的赔率和平均值。
答案 0 :(得分:3)
这应该可以解决问题:
https://jsfiddle.net/7qkd8jwe/3/
.item:nth-child(4n-7) {
background-color:green;
}
.item:nth-child(4n-6) {
background-color:red;
}
.item:nth-child(4n-5) {
background-color:blue;
}
.item:nth-child(4n-4) {
background-color:black;
}
.item {
width:100%;
height:100px;
margin-bottom:10px;
}
答案 1 :(得分:2)
@ambs证明我错了,但无论如何我都会把它留在这里。
我认为使用nth-child不会像你尝试的那样。
然而,你可以将nth-child与相邻的兄弟选择器结合起来:
.item {
width: 100%;
height: 100px;
background-color: green;
margin-bottom: 10px;
}
.item:nth-child(4n+1) {
background-color: green;
}
.item:nth-child(4n+1) + .item {
background-color: red;
}
.item:nth-child(4n+1) + .item + .item {
background-color: blue;
}
.item:nth-child(4n+1) + .item + .item + .item {
background-color: black;
}
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答案 2 :(得分:2)
.item:nth-child(4n-1) {
background-color:blue;
}
.item:nth-child(4n-2) {
background-color:red;
}
.item:nth-child(4n-3) {
background-color:Green;
}
.item:nth-child(4n) {
background-color:black;
}
.item{
width:100%;
height:100px;
margin-bottom:10px;
}
这是一个解决方案。没有技巧