Question

我有三个MySQL表：

例如

表格是菜单ID，名称
B表是customer_order ID，order_date
C表是order_item ID，menu_item_id，customer_order_id，order_quantity

我尝试在本月输出名称，总和（order_quantity）

目前我有两个单独的查询工作正常，但第二个查询在foreach循环内部，看起来不太好。

输出所有菜单项的第一个查询：

$results = $wpdb->get_results( "SELECT * FROM menu WHERE post_id = $pid ORDER BY sort_order ");

第二个查询将输出每个月销售的每件商品的总数：

$total = $wpdb->get_col( "SELECT SUM(oi.order_item_quantity) 
                          from order_item as oi 
                          INNER JOIN customer_order as ho ON ho.ID = oi.order_id  
                          WHERE oi.order_item_id =  $subC->ID AND YEAR(ho.order_date) = $current_year AND MONTH(ho.order_date) = $current_month ");

我尝试将两个查询合并为一个查询，这花了我一整天但仍然无法解决，请有人给我一些帮助。

更新

感谢Rene。

Select m.name, m.name as name, sum(oi.order_item_quantity) as sold_monthly from menu as m left join order_item as oi on oi.order_item_id = m.ID left join cusomter_order as co on co.ID = oi.order_id where m.post_id = 110  group by m.ID, m.name

这将输出

 name                   sold_monthly    
Sushi Lunch Special     NULL
Sushi Lunch             19
Sashimi Lunch           61
jason                   NULL
egg roll                NULL

如果我添加YEAR(co.order_date) = 2016 AND MONTH(co.order_date) = 9

我只得到

 name                   sold_monthly    
Sushi Lunch             7
Sashimi Lunch           14

当我添加YEAR(co.order_date) = 2016 AND MONTH(co.order_date) = 9.

时，我怎么能保持寿司午餐特别，jason，蛋卷，空项目

这里我试试

(year(co.order_date) = 2016 and month(co.order_date) = 10) or sold_monthly is null

给我一个查询错误

更新再次感谢Rene

现在正在使用

 (year(co.order_date) = 2016 and month(co.order_date) = 10) or co.order_date is null

最终解决它，上层有小bug，当我改变business_id时可能无法捕获我想要的结果，所以我要添加一个子查询。

Select m.*, p.sold_monthly from menu as m left join ( SELECT SUM(oi.order_item_quantity) as sold_monthly, oi.order_item_id as ID, oi.order_item_name from order_item as oi LEFT JOIN cusomter_order as ho ON ho.ID = oi.order_id WHERE ho.business_id = $pid AND (year(ho.order_date) = $current_year and month(ho.order_date) = $current_month) OR ho.order_date is NULL GROUP by oi.order_item_id )p on p.ID = m.ID where m.post_id = $pid

Answer 1

因此，您尝试获取每个post_id的列表，该列表受所选月份的限制。以下查询将为以下示例数据生成。

SELECT m.ID as ID, m.Name as Name, SUM(oi.order_quantity) as Quantity
FROM menu as m
LEFT JOIN order_item as oi ON oi.menu_item_id = m.ID 
LEFT JOIN customer_order as co ON co.ID = oi.customer_order_id
WHERE m.post_id = 0 AND YEAR(co.order_date) = 2016 AND MONTH(co.order_date) = 9 OR co.order_date is NULL
GROUP BY m.ID,m.Name,m.sort_order
ORDER BY m.sort_order

样本数据

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";

DROP TABLE IF EXISTS `customer_order`;
CREATE TABLE `customer_order` (
  `ID` int(11) NOT NULL,
  `order_date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_german2_ci;

TRUNCATE TABLE `customer_order`;
INSERT INTO `customer_order` (`ID`, `order_date`) VALUES
(1, '2016-09-06 00:00:00'),
(2, '2016-09-13 00:00:00'),
(3, '2016-08-09 00:00:00'),
(4, '2016-09-19 00:00:00');

DROP TABLE IF EXISTS `menu`;
CREATE TABLE `menu` (
  `ID` int(11) NOT NULL,
  `sort_order` int(11) NOT NULL,
  `post_id` int(11) NOT NULL,
  `Name` varchar(20) COLLATE utf8_german2_ci NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_german2_ci;

TRUNCATE TABLE `menu`;
INSERT INTO `menu` (`ID`, `sort_order`, `post_id`, `Name`) VALUES
(2, 0, 0, 'Test 1'),
(4, 1, 0, 'Test 2'),
(5, 2, 0, 'Test 3');

DROP TABLE IF EXISTS `order_item`;
CREATE TABLE `order_item` (
  `ID` int(11) NOT NULL,
  `menu_item_id` int(11) NOT NULL,
  `customer_order_id` int(11) NOT NULL,
  `order_quantity` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_german2_ci;

TRUNCATE TABLE `order_item`;
INSERT INTO `order_item` (`ID`, `menu_item_id`, `customer_order_id`, `order_quantity`) VALUES
(1, 2, 1, 1),
(2, 2, 2, 3),
(3, 4, 1, 1),
(4, 4, 2, 4),
(5, 2, 3, 3),
(6, 4, 3, 1),
(7, 2, 4, 4);


ALTER TABLE `customer_order`
  ADD PRIMARY KEY (`ID`);

ALTER TABLE `menu`
  ADD PRIMARY KEY (`ID`),
  ADD KEY `idx_pid` (`post_id`);

ALTER TABLE `order_item`
  ADD PRIMARY KEY (`ID`),
  ADD KEY `idx_coid` (`customer_order_id`),
  ADD KEY `idx_miid` (`menu_item_id`);


ALTER TABLE `customer_order`
  MODIFY `ID` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=5;
ALTER TABLE `menu`
  MODIFY `ID` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=6;
ALTER TABLE `order_item`
  MODIFY `ID` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=8;

ALTER TABLE `order_item`
  ADD CONSTRAINT `CostomerOrderConstrain` FOREIGN KEY (`customer_order_id`) REFERENCES `customer_order` (`ID`),
  ADD CONSTRAINT `MenuItemConstrain` FOREIGN KEY (`menu_item_id`) REFERENCES `menu` (`ID`);

祝你好运整合查询，让我知道它是否有效。

更新：更新了样本数据以重现实际问题。更新了解决方案查询。

MySQL连接三个表，项目加入主表的总和

1 个答案: