我可以请一些帮助吗?我是编程的新手。自从我开始编程以来已经过了一周。我一直在研究一个程序,它需要输入一个数字并输出你输入的数字。 我的问题是。这个程序有替代代码吗?另外,如果输入为-1,我如何添加一些代码,它将显示为"否定一个"?我非常感谢你们给予的任何帮助。
这是我一直在工作的代码:
示例输出是: 输入数字:12345 产量:十二千三百四十五
import java.util.Scanner;
public class Numberconvert {
public boolean Number(String s) {
boolean tama = true;
for (int i = 0; i < s.length(); i++) {
if (!Character.isDigit(s.charAt(i))) {
return false;
}
}
return tama;
}
public static String convert(int digit) {
String ArrayOnes[] = {"zero", " One ", " Two ", " Three ", " Four ", " Five ", " Six ", " Seven ", " Eight ", " Nine ", " Ten ",
" Eleven ", " Twleve ", " Thirteen ", " Fourteen ", " Fifteen ", " Sixteen ", " Seventeen ", " Eighteen ", " Ninteen "};
String ArrayOnes2[] = {" ", " Ten ", " Twenty ", " Thirty ", " Fourty ", " Fifty ", " Sixty ", " Seventy ", " Eighty ", " Ninety "};
String ArrayNegative[] = {"Negative "};
if (digit < 0) {
return ArrayNegative[0];
}
if (digit % 10 == 0) {
ArrayOnes[0] = "";
}
if (digit < 20) {
return ArrayOnes[digit];
}
if (digit < 100) {
return ArrayOnes2[digit / 10] + ArrayOnes[digit % 10];
}
if (digit < 10000) //return convert(digit/100)+" Hundred "+convert(digit %100);
{
return convert(digit / 100) + " Thousand " + convert(digit % 100);
}
if (digit < 100000000) {
return convert(digit / 1000) + " Thousand " + convert(digit % 1000);
}
return convert(digit / 1000000000) + " Million " + convert(digit % 1000000000);
//return convert(digit);
}
public static void main(String[] args) {
Scanner scann = new Scanner(System.in);
String Number;
// checker - class to loop until the input is number
Numberconvert checkIfNumber = new Numberconvert();
// convert string in to number
int result;
try {
// this do while method is only to check if the input is Number
do {
System.out.print("Enter a Number: ");
Number = scann.nextLine();
} while (!checkIfNumber.Number(Number));
// this if statement is only works if the input is Number
if (checkIfNumber.Number(Number)) {
// String into int to process the String
result = Integer.parseInt(Number);
// initialize "converted" to the function;
String converted = convert(result);
// print the result
System.out.println(converted);
}
// if ever some error detected. The user want to input again
} catch (Exception e) {
System.out.println("");
System.err.println("Some Errors Detected ");
System.out.println("Want to input again? Press Enter ");
scann.nextLine();
main(null);
}
}
}