为什么我会收到此演员错误?

时间:2016-10-01 18:37:39

标签: java classcastexception

我的项目中有一个Customer对象,用于扩展User对象。

User.java

public class User {

private int userId;
private int user_type;
private String username;
private String password;

public User(int id, int user_type, String username, String password) {
    super();
    this.userId = id;
    this.user_type = user_type;
    this.username = username;
    this.password = password;
}

public int getUserId() {
    return userId;
}
public void setUserId(int userId) {
    this.userId = userId;
}

public int getUser_type() {
    return user_type;
}

public void setUser_type(int user_type) {
    this.user_type = user_type;
}

public String getUsername() {
    return username;
}

public void setUsername(String username) {
    this.username = username;
}

public String getPassword() {
    return password;
}

public void setPassword(String password) {
    this.password = password;
}

}

和我的Customer.java

public class Customer extends User{

private String cartId;

public Customer(int id, int user_type, String username, String password) {
    super(id, user_type, username, password);
    // TODO Auto-generated constructor stub
}

public String getCartId() {
    return cartId;
}

public void setCartId(String cartId) {
    this.cartId = cartId;
}
}

现在,我为我的网站创建了一个简单的登录信息,首先检查用户是否存在,如果存在,则检查是客户还是来自管理层。如果是客户,我有一个获取其购物车ID的方法。然后我将用户转换为客户类型,然后通过setter设置购物车ID。

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    String username = request.getParameter("username");
    String password = request.getParameter("password");
    boolean userDoesNotExist = false;

    User user = ServiceFactory.userService().getUser(username);
    System.out.println(user.getPassword() + " " + user.getUsername());

    if(user != null){
        if(user.getUser_type() == 1){
            String cartId = ServiceFactory.customerService().getCartId(user.getUserId());
            Customer customer = (Customer) user;
            customer.setCartId(cartId);

            request.getSession().setAttribute("customer", customer);
            response.sendRedirect("customer");
        }else{

        }
    }else{
        userDoesNotExist = true;

        request.setAttribute("userDoesNotExist", userDoesNotExist);
        request.setAttribute("username", username);
        RequestDispatcherManager.dispatch(this, "/login.jsp", request, response);
    }
}

所以,回到我的问题,为什么我得到了......

java.lang.ClassCastException: com.qbryx.domain.User cannot be cast to com.qbryx.domain.Customer
com.qbryx.servlets.LoginServlet.doPost(LoginServlet.java:50)
javax.servlet.http.HttpServlet.service(HttpServlet.java:648)
javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

2 个答案:

答案 0 :(得分:1)

这是正确的 - 它是扩展用户的客户,而不是相反。将客户投射到用户总是很好,但是除非对象实际上是客户,否则将用户投射到客户将不会成功。

如果您将“扩展”从Java翻译为英语,您就会得到每个客户都是用户,但不是evry用户是客户。

答案 1 :(得分:1)

  

java.lang.ClassCastException:

在不同层次结构中进行转换(向下转换和向上转换)时会发生此异常。

在这里,您尝试将用户对象(父类)强制转换为客户对象(子类)

Customer customer = (Customer) user;// this is wrong since user is not a customer

为了避免ClassCastException您可以使用instanceof操作员检查

if(user instanceof Customer){
   customer = (Customer) user;
}