Diff条件:如何在每次迭代结束时清除动态图例;如何在每次迭代结束时删除拟合的线性线。
我正在尝试扩展线程Dynamic Legend (Updates in every recursion)的这个答案,以在一个图表上迭代图例。 建议在一个线性图上覆盖动态图例
close all; clear all;
% Test data
aSize=zeros(2,777);
aSize=[[0, 0]' randi(3,2,777)]; % STDEV about 3
x=0:1:180;
hFig=figure;
index=1;
while (index<=7);
% origo left alone
aSize(:, index+1) = aSize(:, index+1) + index; % to have linearly increasing trend
sz=40;
legend('-DynamicLegend');
h = scatter(aSize(1,1:index+1)', aSize(2,1:index+1)', sz, ...
'MarkerEdgeColor',[0 .5 .5],...
'MarkerFaceColor',[0 .7 .7],...
'LineWidth',1.5, ...
'DisplayName', sprintf('Data'));
xlabel('width'); ylabel('height');
hold on;
% Optimum
x=0:1:max( aSize(1, 1:index+1) );
y = x; % assume uniform
grid on;
h1=plot(x,y, 'black', ...
'DisplayName', sprintf('Optimum'));
% Fit with R2 linear
x=aSize(1,1:index+1);
b1 = aSize(1,1:index+1)' \ aSize(2,1:index+1)';
yCalc1 = b1 * aSize(1,1:index+1);
Rsq1 = 1 - sum((y(1:index+1) - yCalc1).^2)/sum((y(1:index+1) - mean(y(1:index+1))).^2)
% origo needed
x = [0 x];
yCalc1 = [0 yCalc1];
h2=plot(x(1:index+2)', yCalc1(1:index+2)', '--p', ...
'DisplayName', sprintf('Fit R2 = %d', Rsq1));
drawnow;
index=index+1;
end;
仅在附加图例的情况下输出不成功
Matlab:2016a
操作系统:Debian 8.5 6位
Linux内核:4.6的backports
硬件:华硕Zenbook UX303UA
答案 0 :(得分:1)
删除此行legend('-DynamicLegend');
并在drawnow
行之前写下,然后在该行后面写hold off
。所以以下是循环结束时的行。
legend('-DynamicLegend');
drawnow;
hold off
index=index+1;