Question

这是我的服务器 - 客户端聊天程序中的客户端代码，但是当我尝试通过发送信件 q 来关闭此程序时，它根本不起作用。它停留在终端并等待一些东西。

我在这里做错了什么？

import socket
import threading
import time

receiving = False
lock = threading.Lock()

def receive(name, sock):
        receiving = True
        while receiving:
                try:
                        lock.acquire()
                        while True:
                                data, address = sock.recvfrom(1024)
                                print str(data)
                except:
                        pass
                finally:
                        lock.release()

host = 'localhost'
port = 0
server = ('localhost', 7787)

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((host, port))
s.setblocking(0)

receiveThread = threading.Thread(target=receive, args=("receiveThread", s))
receiveThread.start()

username = raw_input("Name: ")
message = raw_input(username + "-> ")

while True:
        if message == 'q':
                receiving = False
                receiveThread.join()
                s.close()
                break
        if message != '':
                s.sendto(username + ": " + message, server)
        lock.acquire()
        message = raw_input(username + "-> ")
        lock.release()
        time.sleep(0.2)

如果您有兴趣查看服务器代码，请访问：

import socket
import threading
import time

host = 'localhost'
port = 7787

running = False

MAX_PACKET_SIZE = 1024
clients = []

s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.bind((host, port))
s.setblocking(0)


running = True
print "server started..."

while running:
        try:
                data, address = s.recvfrom(MAX_PACKET_SIZE)
                if 'quit' in str(data):
                        running = False
                        print 'server stopped...'
                if address not in clients:
                        clients.append(address)

                print time.ctime(time.time()) + str(address) + ": :" + str(data)
                for client in clients:
                        s.sendto(data, client)
        except:
                pass

running = False
s.close()

Answer 1

因为你有一个异常块，除了一切。在这种情况下，它还会捕获键盘中断并覆盖终止呼叫。

你应该为KeyboardInterrupt添加一个单独的catch块：

except KeyboardInterrupt:
     raise

Answer 2

因为在python ctrl + C中触发了KeyboardInterrupt异常被抛出。这使您可以优雅地关闭程序。你用

捕获了这个例外

            except:
                    pass

为什么python程序不能用Ctlr + d或Ctrl + c中断？

2 个答案: