我正在尝试运行此查询在where子句中传递% gcc -v
Configured with: --prefix=/Applications/Xcode.app/Contents/Developer/usr --with-gxx-include-dir=/usr/include/c++/4.2.1
Apple LLVM version 8.0.0 (clang-800.0.38)
Target: x86_64-apple-darwin15.6.0
Thread model: posix
InstalledDir: /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin
数组。但是在此$data数组中，一个或多个字段值可以为null，而某些字段不是如下所示： / p>
$data如何根据where子句中的$data = Array(
[c.client_id]=>
[c.conn_type]=>
[c.pkg_id]=> 2
[c.area_id]=> 1
[c.managed_by]=> 3
[c.status]=>
)
function getAllClientByParam($data){
$this->db->select('c.client_id, c.client_name, c.conn_charge, c.con_date, cd.disconnect, c.mobile, p.pkg_name, ct.conn_type, s.status, a.area, m.managed_by, c.remarks');
$this->db->from('bill_client AS c');
$this->db->join('bill_connection_details AS cd','c.client_id=cd.client_id','LEFT');
$this->db->join('bill_pkg AS p','c.pkg_id=p.pkg_id','LEFT');
$this->db->join('bill_connection_type AS ct','c.conn_type=ct.conn_id','LEFT');
$this->db->join('bill_conn_status AS s','c.status=s.id','LEFT');
$this->db->join('bill_area AS a','c.area_id=a.area_id','LEFT');
$this->db->join('bill_managed_by AS m','c.managed_by=m.managed_id','LEFT');
$this->db->where('c.company_id', $this->company_id);
$this->db->where($data);
$client_list = $this->db->get();
$data = $client_list->result();
return $data;
}
变量检索此查询的所有数据？
答案 0 :(得分：0)
在你的示例$ data中，它总是必须包含实际具有值的条目...所以你需要示例$ data ...
$data = array(
'c . pkg_id' => 2,
'c . area_id ' => 1,
'c . managed_by' => 3
);
所以你需要在将$ data数组传递给方法之前构建它。