Question

如何用每个锚文本替换所有锚点。我的代码是

$body='<p>The man was <a href="http://www.example.com/video/">dancing like a little boy</a> while all kids were watching ... </p>';

我希望结果为：

<p>The man was dancing like a little boy while all kids were watching ... </p>

我用过：

$body= preg_replace('#<a href="https?://(?:.+\.)?ok.co.*?>.*?</a>#i', '$1', $body);

结果是：

<p>The man was while all kids were watching ... </p>

Answer 1

试试这个

$body='<p>The man was <a href="http://www.example.com/video/">dancing like a little boy</a> while all kids were watching ... </p>';

    echo preg_replace('#<a.*?>([^>]*)</a>#i', '$1', $body);

Answer 2

没有正则表达式.....

<?php

$d = new DOMDocument();
$d->loadHTML('<p>The man was <a href="http://www.example.com/video/">dancing like a little boy</a> while all kids were watching ... </p>');
$x = new DOMXPath($d);
foreach($x->query('//a') as $anchor){
    $url = $anchor->getAttribute('href');
    $domain = parse_url($url,PHP_URL_HOST);
    if($domain == 'www.example.com'){
        $anchor->parentNode->replaceChild(new DOMText($anchor->textContent),$anchor);
    }
}

function get_inner_html( $node ) {
    $innerHTML= '';
    $children = $node->childNodes;
    foreach ($children as $child) {
        $innerHTML .= $child->ownerDocument->saveXML( $child );
    }
    return $innerHTML;
}
echo get_inner_html($x->query('//body')[0]);

Answer 3

您可以在这里使用strip_tags()和htmlspecialchars()。

strip_tags - 从字符串中删除HTML和PHP标记

htmlspecialchars - 将特殊字符转换为HTML实体

第1步：使用 strip_tags（）删除<p>标记以外的所有标记。

第2步：由于我们需要获取字符串以及HTML标记，因此我们需要使用 htmlspecialchars（）。

echo htmlspecialchars(strip_tags($body, '<p>'));

当已经有一个内置的PHP函数时，我认为使用它而不是使用preg_replace

更好更紧凑

Answer 4

可以使用此代码：

正则表达式： define('DB_SERVER','localhost'); define('DB_USERNAME','xxx'); define('DB_PASSWORD','yyy'); define('DB_NAME','fff'); $conn = mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_NAME); foreach($unique_array as $supplier) { $urep[]=$supplier['rep_name']; $udate[]=$supplier['date']; $ucid[]=$supplier['cid']; $unique_arrayyy[] = array('rep_name'=>$supplier['rep_name'], 'date'=>$supplier['date']); } array_map(function ($var) { $fetch_gdd=mysqli_query($conn,"select * from grade"); echo mysqli_num_rows($fetch_gdd); exit; }, $unique_arrayyy);

/< a.*?>|<a.*?>|<\/a>/g

测试并显示示例匹配字：https://regex101.com/r/mgYjoB/1

带锚文本的preg_replace href锚点

4 个答案: