Question

通过CCDA为实验室工作需要遍历父子和子段，但“Lab”的变量不起作用，但“Section”和“Header”正在工作：

var file=""; var header="";  var Lab=""; var section="";


header=msg['recordTarget']['patientRole']['patient']['name']['family'].toString()+"|"+ //last name msg['recordTarget']['patientRole']['patient']['name']['given'].toString()+"|"+ //first name msg['recordTarget']['patientRole']['patient']['administrativeGenderCode']['@code'].toString()+"|"+ //gender msg['recordTarget']['patientRole']['patient']['birthTime']['@value'].toString(); //DOB msg['component']['structuredBody']['component'][8]['section']['title'].toString()
               for each (seg in msg..component)
                {    Lab = "";
                  Lab =seg['section']['title'].toString();
                  if (section == "Results")
                 {
                   for each (seg in seg..entry..organizer)
                {

                       Lab+= seg ['code']['@code'].toString()+"|"+ //LOINC code
                       seg ['code']['@displayName'].toString()+"|"+//actText
                       seg ['effectiveTime']['@value'].toString();//collection timestamp

                          }
                       }
                } for each (seg in msg..component)
                {
                  section = "";
                  section =seg['section']['title'].toString();
                  if (section == "Results")

                 {
                   for each (seg in seg..entry..organizer..component)
                {

                       file+=header+"|"+Lab+"|"+
                       seg ['observation']['code']['@code'].toString()+"|"+ //LOINC code
                       seg ['observation']['code']['@displayName'].toString()+"|"+//actText
                       seg ['observation']['effectiveTime']['@value'].toString()+"|"+//result timestamp
                       seg ['observation']['value']['@value'].toString()+"|"+//result value
                       seg ['observation']['value']['@unit'].toString()+"|"+//result unit
                       seg ['observation']['interpretationCode']['@code'].toString()+"!!!"+"\r"+"\n";//interpretationCode

                          }
                       }
                }

channelMap.put("FILE",file);

Answer 1

＆＃39;每个＆＃39;已弃用，请使用＆＃39;;

第2行有语法错误（单行注释）标题= ...

该陈述应分为几行

 header=msg['recordTarget']['patientRole']['patient']['name']['family'].toString()+"|"+ //last name
 msg['recordTarget']['patientRole']['patient']['name']['given'].toString()+"|"+ //first name 
 msg['recordTarget']['patientRole']['patient']['administrativeGenderCode']['@code'].toString()+"|"+ //gender 
 msg['recordTarget']['patientRole']['patient']['birthTime']['@value'].toString(); //DOB 
 msg['component']['structuredBody']['component'][8]['section']['title'].toString();

点点语法仅适用于数字文字

556..toString()==="556"

全部替换.. （单点）

第一个循环部分中的

永远不会改变其初始值＆＃34;＆＃34 ;; section ==＆＃34; Results＆＃34;总是判断为false，后续的if分支永远不会执行。

你正在使用xml到json解析器吗？我不相信侯需要调用toString（）演员表是自动完成的（字符串+某些内容由解释器转换为字符串+ something.toString（））

var file="",
  header="",
  Lab="",
  section="";


header=msg['recordTarget']['patientRole']['patient']['name']['family'].toString()+"|"+ //last name
  msg['recordTarget']['patientRole']['patient']['name']['given'].toString()+"|"+ //first name 
  msg['recordTarget']['patientRole']['patient']['administrativeGenderCode']['@code'].toString()+"|"+ //gender 
  msg['recordTarget']['patientRole']['patient']['birthTime']['@value'].toString(); //DOB 
  msg['component']['structuredBody']['component'][8]['section']['title'].toString();

for(seg in msg.component){
  Lab = "";
  Lab =seg['section']['title'].toString();
  if (section == "Results"){
      for(seg in seg  .entry  .organizer){

     Lab+= seg ['code']['@code'].toString()+"|"+ 
        //LOINC code
      seg ['code']['@displayName'].toString()+"|"+
        //actText
      seg ['effectiveTime']['@value'].toString();
        //collection timestamp

    }
  }
}

for(seg in msg.component){
  section = "";
  section =seg['section']['title'].toString();
  if (section == "Results"){
   for(seg in seg.entry.organizer.component){
    file+=header+"|"+Lab+"|"+
    seg ['observation']['code']['@code'].toString()+"|"+
      //LOINC code
    seg ['observation']['code']['@displayName'].toString()+"|"+
      //actText
    seg ['observation']['effectiveTime']['@value'].toString()+"|"+
      //result timestamp
    seg ['observation']['value']['@value'].toString()+"|"+
      //result value
    seg ['observation']['value']['@unit'].toString()+"|"+
      //result unit
    seg ['observation']['interpretationCode']['@code'].toString()+"!!!"+"\r"+"\n";
      //interpretationCode
    }
  }
}

channelMap.put("FILE",file);

在欢乐中结合嵌套的foreach循环

1 个答案: