Question

我正在运行Debian 6.0，我正在尝试在启动时使用一个非常简单的init脚本。

我正在运行以下命令：

$ cd /etc/init.d

$ pico script

#! /bin/sh
### BEGIN INIT INFO
# Provides:          script
# Required-Start:    $remote_fs $syslog
# Required-Stop:     $remote_fs $syslog
# Default-Start:     2 3 4 5
# Default-Stop:      0 1 6
# Short-Description: Start daemon at boot time
# Description:       Enable service provided by script.
### END INIT INFO

# PATH should only include /usr/* if it runs after the mountnfs.sh script
PATH="$PATH:/usr/local/bin"
DESC="script..."
NAME=script
DAEMON=/usr/sbin/$NAME
DAEMON_ARGS="--options args"
PIDFILE=/var/run/$NAME.pid
SCRIPTNAME=/etc/init.d/$NAME

# Some things that run always
echo "Welcome!!!!!" | tee /$HOME/hello.txt

# Carry out specific functions when asked to by the system
case "$1" in
  start)
    echo "Starting script blah "
    echo "Could do more here"
    ;;
  stop)
    echo "Stopping script blah"
    echo "Could do more here"
    ;;
reload)
    echo "reload"
    ;;
    *)
    echo "Usage: /etc/init.d/blah {start|stop}"
   exit 1
    ;;
esac

exit 0

$ chmod 755脚本

$ chown root：root script

$ insserv脚本

确实使用./script start。但它不是在启动时。

**我使用 insserv 而不是 update-rc.d ，因为我收到此错误：

＆＃34; update-rc.d：使用基于依赖关系的启动顺序＆＃34;

我错过了什么？ =（

如何在启动时运行debian脚本？

0 个答案: