Question

公共类MainActivity扩展了AppCompatActivity {

Spinner spinner;
ArrayAdapter<CharSequence> adapter;

int noc = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    spinner =(Spinner)findViewById(R.id.spinner);
    String text= spinner.getSelectedItem().toString();
    adapter= ArrayAdapter.createFromResource(this,R.array.Coffee_names,android.R.layout.simple_spinner_item);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener(){
        @Override
        public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
            Toast.makeText(getBaseContext(),parent.getItemIdAtPosition(position) + " is selected",Toast.LENGTH_SHORT).show();

        }

        @Override
        public void onNothingSelected(AdapterView<?> parent) {

        }
    });
}

当我将“String text = spinner.getSelectedItem（）。toString（）;”添加到我的代码中时，我的应用程序停止，但是当我从程序中删除此行时，它可以正常工作。但是当我从下拉列表中选择一个项目时，它会选择4。我希望它说出我选择的项目的名称而不是索引值。请帮忙。

Answer 1

我认为应该是：

Toast.makeText(getBaseContext(), parent.getSelectedItem() + " is selected", Toast.LENGTH_SHORT).show();

Answer 2

替代方式

final String[] coffeeNames = getResources().getStringArray(R.array.Coffee_names);
spinner.setAdapter(new ArrayAdapter<>(activity, android.R.layout.simple_list_item_1, coffeeNames));
spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener(){
    @Override
    public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {
        String selectedCoffeeName = coffeeNames[position];
        Toast.makeText(getBaseContext(), selectedCoffeeName + " is selected", Toast.LENGTH_SHORT).show();
    }

    @Override
    public void onNothingSelected(AdapterView<?> parent) {

    }
});

如何获取微调器值不是整数而是字符

2 个答案: