Question

我有一个问题：我如何将新游戏放入代码或PlayAgain（y）或（n）这是我的学校项目。我一直试图找到一个解决方案，但它只会重复“再次播放”或错误的问题。

    import random

    player1 = input("Enter your real name: ")
    player2 = "Computer"

    state = random.randint(12,15)
    print("The number of sticks is " , state)
    while(True):
        print(player1)
        while(True):
            move = int(input("Enter your move: "))
            if move in (1,2,3) and move <= state:
                break
            print("Illegal move") 
        state = state - move
        print("The number of sticks is now " , state)
        if state == 0:
            print(player1 , "wins")
            break
        print(player2)
        move = random.randint(1,3)
        if state in (1,2,3):
            move = state
        print("My move is " , move)
        state = state - move
        print("The number of sticks is now " , state)
        if state == 0:
            print("Computer wins")
            break

Answer 1

您的循环条件始终为True。这是需要调整的。相反，您只想在用户想要继续时循环

choice = 'y'  # so that we run at least once
while choice == 'y':
    ...
    choice = input("Play again? (y/n):")

每次开始新游戏时，您都必须确保重置状态。

由于您的游戏可以结束多个点，因此您需要重构代码或替换break。例如

if state == 0:
    print(player1 , "wins")
    choice = input("Play again? (y/n):")
    continue

或者更容易将游戏置于内循环中

choice = 'y'
while choice == 'y':
  while True:
    ...
    if state == 0:
      print(player1, "wins")
      break
    ...
  choice = input("Play again? (y/n):")

在那时，如果我是你，我会开始将事情分解为函数

Python NIM游戏：我如何添加新游戏（y）或（n）

1 个答案: