Question

我有一个我试图运行的程序。它编译但没有按预期运行（它仅部分运行）：

#include <stdio.h>

int main(int argc, const char * argv[]) {

char play;
char choice;
char answer;

printf("Welcome to Two doors.\n");
printf("Would you like to play? (y/n): ");
scanf("%c", &play);

if (play == 'y') {

    printf("\nYou are a prisoner in a room with 2 doors and 2 guards.\n");
    printf("One of the doors will guide you to freedom and behind the other is a hangman --you don't know which is which.\n");
    printf("One of the guards always tells the truth and the other always lies. You don't know which one is the truth-teller or the liar either.\n");
    printf("You have to choose and open one of these doors, but you can only ask a single question to one of the guards.\n");
    printf("What do you ask so you can pick the door to freedom?\n\n");
    printf("\t1.Ask the truth-guard to point to the door of doom.\n");
    printf("\t2.Ask the liar-guard to point to the door of doom.\n");
    printf("\t3.Doesn't matter which one you pick.\n");
    scanf("%c", &choice);

    char answer = "No matter which one you choose the guards both tell you which door leads to death, and therefore you can pick the other door.\n";
    switch (choice) {
        case 1:
            printf("%c", answer);
            break;
        case 2:
            printf("%c", answer);
            break;
        case 3:
            printf("%c", answer);
            break;
        default:
            break;
    }
}

return 1;
}

似乎我无法让代码完整地运行。这是我在进入＆＃39; y＆＃39;之后运行它时得到的。问题：

Welcome to Two doors.
Would you like to play? (y/n): y

You are a prisoner in a room with 2 doors and 2 guards.
One of the doors will guide you to freedom and behind the other is a hangman --you don't know which is which.
One of the guards always tells the truth and the other always lies. You don't know which one is the truth-teller or the liar either.
You have to choose and open one of these doors, but you can only ask a single question to one of the guards.
What do you ask so you can pick the door to freedom?

    1.Ask the truth-guard to point to the door of doom.
    2.Ask the liar-guard to point to the door of doom.
    3.Doesn't matter which one you pick.
(lldb)

有没有人可以帮我解决这个问题？

谢谢！

Answer 1

 char answer = "No matter which one you choose the guards both tell you which door leads to death, and therefore you can pick the other door.\n";

这当然是错的。 answer是char，只能包含单个字符而非字符串文字。

您需要使用char *或char []并使用%s进行打印。

Answer 2

answer是char类型变量，您无法为其指定字符串。

Answer 3

answer需要具有const char *类型。
将switch (choice) { case 1:更改为switch (choice) { case '1':

Answer 4

问题在于，当用户按下Enter键表示他们想要播放时，他们实际上正在发送第二个字符。因此，choice设置为\n。

有一些事情需要改变：

char answer = "... - ＆gt; char answer[] = "...
在切换中将'放在数字周围（例如1 - ＆gt; '1'）
跳过选择的换行符。

我对第3号的第一个想法是这样的：

do{
    scanf("%c", &choice);
} while(choice != '1' && choice != '2' && choice != '3');

Answer 5

printf()部分中的switch语句缺少换行符（\n）。根据您的终端，这可能会导致输出被隐藏。使用：printf("%c\n", answer);

程序没有完全运行

5 个答案: