首先，我不确定我的代码中是否遗漏了除我的函数中的问题之外的任何内容，但我离题了。我是jquery的新手，所以我在设置注册页面时遇到了困难。在我试图检查有效条目以及使用php检查后端查询的形式。我设置了2个文件，一个是html文件，另一个是php文件。使用ajax函数应该调用php文件，但我似乎无法使它工作，我想知道我是否应该把所有代码放在同一个文件中。此外，我不确定这些功能是否正常工作，因为它没有返回任何状态。我将发布下面两个文件的代码。任何提示或提示将不胜感激。
没有css的HTML文件
<!DOCTYPE html>
<html >
<head>
<meta charset="UTF-8">
<title>Register</title>
<link rel="stylesheet" href="assets/css/reset.css">
<link rel="stylesheet" href="assets/css/style.css">
</head>
<body>
<script src="assets/js/jquery.min.js"> </script>
<script src="assets/js/main.js"> </script>
<div class="pen-title">
<h1>Registration Form</h1></div>
<script>
function emptyElement(x){
_(x).innerHTML = "";
}
function signup(){
var u = _("username").value;
var e = _("email").value;
var p1 = _("pass").value;
var p2 = _("pass2").value;
var status = _("status");
if(u == "" || e == "" || p1 == "" || p2 == ""){
status.innerHTML = "Fill out all of the form data";
} else if(p1 != p2){
status.innerHTML = "Your password fields do not match";
} else
{
_("submit").style.display = "none";
status.innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "registration.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText != "signup_success"){
status.innerHTML = ajax.responseText;
_("submit").style.display = "block";
} else {
window.scrollTo(0,0);
_("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
}
}
}
ajax.send("u="+u+"&e="+e+"&p="+p1);
}
}
</script>
<!-- Form Module-->
<div class="module form-module">
<div class="form">
</div>
<div class="form">
<h2>Create an account</h2>
<form method="post" name="signupform" id="signupform" onsubmit="return false;">
<input type="text" id="username" onfocus="emptyElement('status')" placeholder="Username" maxlength="50"/>
<input type="password" id="pass" onfocus="emptyElement('status')" placeholder="Password" maxlength="10"/>
<input type="password" id="pass2" onfocus="emptyElement('status')" placeholder="Confirm Password" maxlength="10"/>
<input type="email" id="email" onfocus="emptyElement('status')" placeholder="Email Address" maxlength="50"/>
<!-- <input type="tel" name="telephone" placeholder="Phone Number" maxlength="10"/> -->
<button type="submit" onclick="signup()" name="submit">Register</button>
</form>
</div>
</div>
</body>
</html>
PHP文件
<?php
// Connects to your Database
$host="myhost"; // Host name
$username="myuser"; // Mysql username
$password="mypass"; // Mysql password
$db_name="mydbname"; // Database name
$con = mysqli_connect("$host", "$username", "$password", "$db_name") or die(mysql_error());
// Ajax calls this REGISTRATION code to execute
if(isset($_POST["u"])){
// GATHER THE POSTED DATA INTO LOCAL VARIABLES
$u = preg_replace('#[^a-z0-9]#i', '', $_POST['u']);
$e = mysqli_real_escape_string($con, $_POST['e']);
$p = $_POST['p'];
// GET USER IP ADDRESS
$ip = preg_replace('#[^0-9.]#', '', getenv('REMOTE_ADDR'));
// DUPLICATE DATA CHECKS FOR USERNAME AND EMAIL
$sql = "SELECT id FROM users WHERE username='$u' LIMIT 1";
$query = mysqli_query($con, $sql);
$u_check = mysqli_num_rows($query);
// -------------------------------------------
$sql = "SELECT id FROM users WHERE email='$e' LIMIT 1";
$query = mysqli_query($con, $sql);
$e_check = mysqli_num_rows($query);
// FORM DATA ERROR HANDLING
if($u == "" || $e == "" || $p == ""){
echo "The form submission is missing values.";
exit();
} else if ($u_check > 0){
echo "The username you entered is alreay taken";
exit();
} else if ($e_check > 0){
echo "That email address is already in use in the system";
exit();
} else if (strlen($u) < 3 || strlen($u) > 16) {
echo "Username must be between 3 and 16 characters";
exit();
} else if (is_numeric($u[0])) {
echo 'Username cannot begin with a number';
exit();
} else {
// END FORM DATA ERROR HANDLING
// Begin Insertion of data into the database
// Hash the password and apply your own mysterious unique salt
//$cryptpass = crypt($p);
//include_once ("php_includes/randStrGen.php");
//$p_hash = randStrGen(20)."$cryptpass".randStrGen(20);
// Add user info into the database table for the main site table
$sql = "INSERT INTO users (username, email, password, ip, signup, lastlogin, notescheck)
VALUES('$u','$e','$p' ,'$ip',now(),now(),now())";
$query = mysqli_query($con, $sql);
$uid = mysqli_insert_id($con);
// Establish their row in the useroptions table
$sql = "INSERT INTO useroptions (id, username, background) VALUES ('$uid','$u','original')";
$query = mysqli_query($db_conx, $sql);
// Create directory(folder) to hold each user's files(pics, MP3s, etc.)
//if (!file_exists("user/$u")) {
// mkdir("user/$u", 0755);
//}
}
}
?>
答案 0 :(得分：2)
您的javascript代码有很多错误。就像你使用_而不是$和你的元素ID错误。它们不包括＃。所以我用你的逻辑组织了你的代码。这不是一个真正的问题，也不是一个真正的学习方式。 HTML
<!DOCTYPE html>
<html >
<head>
<meta charset="UTF-8">
<title>Register</title>
<link rel="stylesheet" href="assets/css/reset.css">
<link rel="stylesheet" href="assets/css/style.css">
</head>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
<!--script src="assets/js/main.js"> </script-->
<div class="pen-title">
<h1>Registration Form</h1></div>
<script>
function emptyElement(x){
$('#' + x).text("");
}
function signup(){
var un = $("#username").val();
var em = $("#email").val();
var p1 = $("#pass").val();
var p2 = $("#pass2").val();
if(un == "" || em == "" || p1 == "" || p2 == "")
{
$('#status').text("Fill out all of the form data");
}
else if(p1 != p2)
{
$('#status').text("Your password fields do not match");
}
else
{
$.ajax({
type: "POST",
url: "registration.php",
dataType: "json",
data : { u: un, p:p1, e:em },
cache: !1,
beforeSend: function(){
$("#submit").hide();
$('#status').text('please wait ...');
},
complete: function(){
$("#submit").show();
},
success: function(answer){
if(answer.result == "successful")
{
$("#status").html(answer.text);
}
else
{
$("#status").html(answer.result);
}
},
error: function(answer){
$("#status").text(answer);
}
});
}
/*
var ajax = ajaxObj("POST", "registration.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
if(ajax.responseText != "signup_success"){
status.innerHTML = ajax.responseText;
$("submit").style.display = "block";
} else {
window.scrollTo(0,0);
$("signupform").innerHTML = "OK "+u+", check your email inbox and junk mail box at <u>"+e+"</u> in a moment to complete the sign up process by activating your account. You will not be able to do anything on the site until you successfully activate your account.";
}
}
}
ajax.send("u="+u+"&e="+e+"&p="+p1);
*/
}
</script>
<!-- Form Module-->
<div class="module form-module">
<div class="form">
</div>
<div class="form">
<h2>Create an account</h2>
<form method="post" name="signupform" id="signupform" onsubmit="return false;">
<input type="text" id="username" onfocus="emptyElement('status')" placeholder="Username" maxlength="50"/>
<input type="password" id="pass" onfocus="emptyElement('status')" placeholder="Password" maxlength="10"/>
<input type="password" id="pass2" onfocus="emptyElement('status')" placeholder="Confirm Password" maxlength="10"/>
<input type="email" id="email" onfocus="emptyElement('status')" placeholder="Email Address" maxlength="50"/>
<!-- <input type="tel" name="telephone" placeholder="Phone Number" maxlength="10"/> -->
<button type="submit" onclick="signup()" name="submit">Register</button>
<div id="status"></div>
</form>
</div>
</div>
</body>
</html>
和registration.php
<?php
$answer = new stdClass;
if(isset($_POST))
{
$answer->result = "successful";
$answer->text = "";
foreach($_POST as $key => $value)
{
$answer->text .= $key . ": " . $value . "<br />";
}
}
else
{
$answer->result = "Error";
$answer->text = "Error Message";
}
echo json_encode($answer);
?>
这个registration.php就是一个例子。你可以用你的逻辑重写。 您应该使用$ answer对象进行响应 $ answer-＆gt;结果是repsonse的状态 $ answer-＆gt;文字是回复 我希望它会对你有所帮助。