输入任何没有下标成员的swift 3

Question

我的代码就是这个

import UIKit
import Alamofire

class ViewController: UIViewController {


var young = "https://jsonplaceholder.typicode.com/posts"


override func viewDidLoad() {
    super.viewDidLoad()

    callAlamo(url: young)
}

func callAlamo(url: String){

    Alamofire.request(url).responseJSON { (response) in
        let responseJSON = response.data
        if responseJSON  == nil{
           print("response is empty")
        }else{
            print("Jon is \(responseJSON)")

            self.parseJson(JSONData: responseJSON!)
        }

    }
}

func parseJson(JSONData: Data){

    do{
        let readableJSON = try JSONSerialization.jsonObject(with: JSONData, options: .mutableContainers)

        for  i in 0..<(readableJSON as AnyObject).count{
            print(readableJSON[i] as String)
        }

    }catch{
        print(error)
    }
}  
}

我需要这个Json中的每个数组元素。

Answer 1

尝试使用以下代码：

Alamofire.request(url).responseJSON { (response) in

        switch response.result {
        case .success(let value) :

            print(response.request)  // original URL request
            print(response.response) // HTTP URL response
            print(response.data)     // server data
            print(response.result)   // result of response serialization

            if let JSON = response.result.value as! [String:AnyObject]!{
                print("JSON: ",JSON)
            }
        case .failure(let encodingError):
            completionHandler(APIResponse.init(status: "failure", response: nil, result:nil))
        }
    }

Answer 2

使用responseJSON处理程序时，JSON已在JSONSerialization内部解析Alamofire.request(url).responseJSON { response in if let json = response.result.value { print("Parsed JSON: \(json)") // Now you can cast `json` to a Dictionary or Array } } 数据。您 NOT 想要再次尝试解析它，否则您将解析服务器的响应数据两次，这对性能非常不利。您需要做的就是：

FlipView.Loaded