我有以下Firebase数据库结构
"-KSupX7CppMD1zbqIy0y" : {
"addedByUser" : "zQpb7o18VzYsSoTQtT9DNhOqTUn2",
"content" : "Post 1",
"cost" : "20",
"duration" : "Weekly",
"latitude" : "40.7594479995956",
"longitude" : "-73.9838934062393",
"timestamp" : "Fri 30 Sep"
},
"-KSuphuqO6a0lnrJYUkt" : {
"addedByUser" : "zQpb7o18VzYsSoTQtT9DNhOqTUn2",
"content" : "Post 2",
"cost" : "10",
"duration" : "Daily",
"latitude" : "40.7594329996462",
"longitude" : "-73.9846261181847",
"timestamp" : "Fri 30 Sep"
}
我需要在一定距离参数(小于50米,100米,150米和200米)内过滤帖子。我可以从经度"经度获得坐标。 &安培; "纬度"但是我很难过滤这些帖子。任何帮助将不胜感激。
非常感谢提前。新手到Firebase&迅速的。
答案 0 :(得分:0)
以下是您可以尝试的解决方案。这假设您已将所有帖子从Firebase下载到应用程序并存储在数组中。你也可以考虑使用我没有亲自使用的GeoFire(但我想)。我相信它允许您按位置查询Firebase,因此您不必首先将所有帖子下载到用户的设备并在客户端进行过滤。
// assumes you have set up the app to get the user's current location
var currentLocation: CLLocation?
// Your array of posts downloaded from Firebase
var postArray = [post]()
let metersInTwentyFiveMiles = 40233.6
// You could put this in viewDidAppear after you load the post array from Firebase
for post in postArray {
var distanceInMeters: CLLocationDistance = 0
let postLocation = CLLocation(latitude: post.latitude, longitude: post.longitude)
if let currentLocation = self.currentLocation {
// Set distanceInMeters to the distance between the user's current location and the location of the post.
distanceInMeters = currentLocation.distanceFromLocation(postLocation)
// If this distance is not within 25 miles, remove this post from the array
if self.metersInTwentyFiveMiles < distanceInMeters {
self.posts = self.posts.filter{ $0 != post }
}
}
}
答案 1 :(得分:0)
对于像这样的JSON: -
UsersLocation :{
autoID1 : {....},
autoID2 : {.....}
}
试试这个: -
FIRDatabase.database().reference().child("UsersLocation").queryOrdered(byChild: "lat").queryStarting(atValue: 30).queryEnding(atValue: 60).observeSingleEvent(of: .value, with: {(snap) in
print(snap)
if let snapDict = snap.value as? [String:AnyObject]{
for each in snapDict{
print(each)
}
}
})
}
这将为所有用户提供autoID
密钥,其纬度在30到60之间。您检索数据的顺序将是随机的,因此要按升序迭代它们,您可以对你收到的字典。