我创建了一个html页面,用户在等待另一个应用程序重新启动时会查看该页面。我创建了一个javascript脚本,它向应用程序发出多个请求,直到应用程序返回200.但是,当我尝试打开我的html页面时,浏览器只是崩溃了。任何人都可以看到我的代码有什么问题:
var responseStatus = 404;
var numberOfTries = 0;
var request = new XMLHttpRequest();
while(responseStatus != 200){
console.log("Checking if restart has completed. Attempt number: " + numberOfTries);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
numberOfTries++;
console.log("Restart has not yet completed! NumberOfTries: " + numberOfTries);
}
}
};
request.send();
}
console.log("Server has successfully restarted");
答案 0 :(得分:3)
这样做的最佳方式(在我看来)实际上是结合@ serge1peshcoff的两个选项。将调用编写为在响应失败时调用自身的函数,和在执行此操作时设置超时。在大多数情况下,您不希望在上一个请求之后立即发送另一个请求,您希望等待至少一秒或五秒以防止向服务器发送垃圾邮件(您也没有说明您期望的客户端数量。这是什么糟糕的浏览器可能对服务器来说很糟糕,甚至可能在您的网络应用程序完全启动并返回200之前处理请求。
此外,setTimeout是比setInterval更好的方法,因为您在每次往返时都明确重置它。
借用@serge:
function tryRequest(numTries) {
var responseStatus = 404;
var request = new XMLHttpRequest();
numTries = numTries || 0;
console.log("Checking if restart has completed. Attempt number: " + numAttempts);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
numTries++
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
console.log("Restart has not yet completed! NumberOfTries: " + this.attempts);
setTimeout(tryRequest.bind(null, numTries), 5000); // five seconds
}
}
};
request.send();
console.log("Server has successfully restarted");
}
tryRequest();
答案 1 :(得分:1)
您的方法会发送多个请求,但不会等待他们回复。
以下是它的工作原理:
XMLHttpRequest
while
循环结束并再次运行,而不是等待回调运行结果,创建了很多XMLHttpRequest
个对象,同时运行了很多请求,这不是你想要的。
你可以这两种方式:
第一种方法:
function tryRequest(numAttempts) {
var responseStatus = 404;
var request = new XMLHttpRequest();
console.log("Checking if restart has completed. Attempt number: " + numAttempts);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
console.log("Restart has not yet completed! NumberOfTries: " + numAttempts);
tryRequest(numAttempts + 1)
}
}
};
request.send();
console.log("Server has successfully restarted");
}
tryRequest(0);
第二种方法:
var responseStatus = 404;
var numberOfTries = 0;
var request = new XMLHttpRequest();
var interval = setInterval(tryRequest, 1000)
function tryRequest() {
console.log("Checking if restart has completed. Attempt number: " + numberOfTries);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
numberOfTries++;
console.log("Restart has not yet completed! NumberOfTries: " + numberOfTries);
} else {
clearInterval(interval);
console.log("Server has successfully restarted");
}
}
};
request.send();
}
}
(免责声明:我当时没有对它们进行测试)
答案 2 :(得分:0)
您可以使用
之类的代码var responseStatus = 404;
var numberOfTries = 0;
function check(){
var request = new XMLHttpRequest();
console.log("Checking if restart has completed. Attempt number: " + numberOfTries);
request.open('GET', 'applicationurl', true);
request.onreadystatechange = function(){
if (request.readyState === 4){
console.log("Request Status: " + request.status);
responseStatus = request.status;
console.log("Response Status: " + request.status);
if (request.status != 200) {
numberOfTries++;
console.log("Restart has not yet completed! NumberOfTries: " + numberOfTries);
var tmp = setTimeout(function(){ check() },5000 ); // check after 5 second
} elseif (request.status == 200) {
console.log("Server has successfully restarted");
}
}
};
request.send();
}
//第一次来电
check();