我试图实现一个自定义segue,它将为viewcontroller带来从右到左的动画效果。问题是,当我按下按钮以执行segue到所需的控制器时,我的应用程序崩溃。我收到以下错误:
无法创建类'(null)'
的segue
我是如何实现它的? 我创建了一个新类,并使用以下代码覆盖perform函数:
import UIKit
class CustomTransition: UIStoryboardSegue {
override func perform()
{
let src = self.source
let dst = self.destination
src.view.superview?.insertSubview(dst.view, aboveSubview: src.view)
dst.view.transform = CGAffineTransform(translationX: -src.view.frame.size.width, y: 0)
UIView.animate(withDuration: 0.25,
delay: 0.0,
options: UIViewAnimationOptions.curveEaseInOut,
animations: {
dst.view.transform = CGAffineTransform(translationX: 0, y: 0)
},
completion: { finished in
src.present(dst, animated: false, completion: nil)
}
)
}
}
在我的故事板中,我有一个UIButtoon,我使用自定义segue(由我的CustomTransition类生成的一个)绑定。当我运行应用程序并点击按钮时,我的应用程序崩溃,上面发布了错误。我不明白为什么会崩溃。我发现网上的每篇文章都与我实现它的方式类似。
答案 0 :(得分:1)
你是否尝试过不使用segues而是为此目的进行过渡?
// create transition
let transition = CATransition()
transition.duration = 0.3
// check other types
transition.type = kCATransitionMoveIn
// move from left
transition.subtype = kCATransitionFromLeft
transition.timingFunction = CAMediaTimingFunction(name: kCAMediaTimingFunctionEaseInEaseOut)
navigationController.view.layer.addAnimation(transition, forKey: kCATransition)
// push controller
navigationController.pushViewController(controller, animated: false)
答案 1 :(得分:0)
您可以将该代码提取到Segue类并在Storyboard上使用:
LeftToRightSegue.h:
@interface LeftToRightSegue : UIStoryboardSegue
@end
LeftToRightSegue.m
@implementation LeftToRightSegue
-(void)perform
{
CATransition * transition = [CATransition new];
transition.duration = 1;
transition.type = kCATransitionMoveIn;
transition.subtype = kCATransitionFromLeft;
transition.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut];
[self.sourceViewController.navigationController.view.layer addAnimation:transition forKey:kCATransition];
[self.sourceViewController.navigationController pushViewController:self.destinationViewController animated:false];
}
@end