Mysql独占左加入一对多的关系

Question

我有这两个表

facilities
+----+--------------------------------------+--------------+-------+------+------------+------------+
| id | name                                 | category     | image | cust | created_at | updated_at |
+----+--------------------------------------+--------------+-------+------+------------+------------+
|  1 | Bar                                  | hotel        |       |      | NULL       | NULL       |
|  2 | Minibar in alle Zimmer               | hotel        |       |      | NULL       | NULL       |
|  3 | Snack restaurant                     | hotel        |       |      | NULL       | NULL       |
|  4 | Grillroom                            | hotel        |       |      | NULL       | NULL       |
+----+--------------------------------------+--------------+-------+------+------------+------------+

表 - 2

resortfacilities

+----+------+---------------------+---------------------+------+
| id | f_id | created_at          | updated_at          | h_id |
+----+------+---------------------+---------------------+------+
| 42 | 4    | 2016-09-21 13:17:27 | 2016-09-21 13:17:27 |   35 |
| 59 | 1    | 2016-09-22 10:23:27 | 2016-09-22 10:23:27 |   38 |
| 60 | 4    | NULL                | NULL                |   38 |
+----+------+---------------------+---------------------+------+

我在sql

之后运行了这个

SELECT
facilities.id,
facilities.`name`,
facilities.image,
resortfacilities.h_id
FROM
facilities
LEFT JOIN resortfacilities ON facilities.id = resortfacilities.f_id
WHERE
resortfacilities.f_id IS NULL AND
facilities.category = 'hotel' OR
resortfacilities.h_id <> 35

期望得到以下结果

+----+---------------------------+-------+------+
| id | name                      | image | h_id |
+----+---------------------------+-------+------+
|  4 | Grillroom                 |       |   38 |
|  2 | Minibar in alle Zimmer    |       | NULL |
|  3 | Snack restaurant          |       | NULL |
+----+---------------------------+-------+------+

没有属于h_id 35的值，但我最终得到了

+----+---------------------------+-------+------+
| id | name                      | image | h_id |
+----+---------------------------+-------+------+
|  1 | Bar                       |       |   38 |
|  4 | Grillroom                 |       |   38 |
|  2 | Minibar in alle Zimmer    |       | NULL |
|  3 | Snack restaurant          |       | NULL |
+----+---------------------------+-------+------+

我可以知道如何获得该结果吗？

Answer 1

使用以下脚本（用于获取上述结果）。

SELECT
 f.id,
 f.`name`,
 f.image,
 r.h_id
FROM
facilities f
LEFT JOIN resortfacilities r ON f.id = f.f_id AND r.h_id <> 35
WHERE f.category = 'hotel'