使用mysql查找第一行计数和第二行计数

Question

我在mySql中有一个表。我需要找到表中只有一次进入的条目和第二次进入的另一条记录。请看截图。 count基于shg_id。

Answer 1

如果它具有id属性，则应执行以下操作：

Sub FormatHyperlink()
    ' set up a sample document
    Dim doc As Document
    Set doc = Application.Documents.Add

    Selection.TypeText "This is a hyperlink to the "
    Selection.Collapse wdCollapseEnd
    Selection.Hyperlinks.Add Selection.Range, _
        "https://stackoverflow.com/", , , "greatest webpage"
    Selection.TypeText " ever."

    ' retrieve the hyperlink
    Dim lnk As Hyperlink
    Set lnk = ActiveDocument.Hyperlinks(1)

    ' retrieve the field code of the hyperlink
    Dim rng As Range
    Set rng = lnk.Range.Duplicate
    rng.TextRetrievalMode.IncludeFieldCodes = True

    Dim fieldCodeLength As Integer
    fieldCodeLength = Len(rng.Text)

    rng.TextRetrievalMode.IncludeFieldCodes = False

    ' format the first word of the display text with a different color
    rng.Start = rng.Start + fieldCodeLength + 1
    rng.Collapse
    rng.MoveEnd wdWord, 1
    rng.Font.ColorIndex = wdRed

    ' format the rest of the hyperlink with another color
    Set rng = lnk.Range.Duplicate
    rng.Start = rng.Start + fieldCodeLength + 1
    rng.MoveStart wdWord, 1
    rng.Font.ColorIndex = wdDarkBlue ' or use rng.Font.TextColor = RGB(x,x,x)
End Sub

或者

SELECT * FROM Table
HAVING COUNT(shg_id) = 1 -- Record equal to 1

已更新 - 这在我身边很有效：

SELECT * FROM Table
HAVING COUNT(shg_id) = 2 -- Record equal to 2

另一个 - 稍微取自OTARIKI：

SELECT COUNT(shg_id) AS Total 
FROM Table
WHERE shg_id= 4
GROUP BY shg_idHAVING COUNT(shg_id) = 1

Answer 2

如果我正确理解，你需要这个：

select entered, count(*) from (
    select shg_id, count(*) as entered 
    FROM mytable 
    group by shg_id 
    having count(*) between 1 and 2
)t
group by entered