Question

我想将数组1与数组2进行比较，数组1包含对象数组。数组2中可用的任何项目也应该在数组1上可用。如果是这样，那么，我必须将项目从数组2推送到新数组，然后，我返回新创建的finalArray。我做了代码，它正如我提到的那样工作正常，但是，下面的代码执行'for loop'许多我不想要的项目。

我想避免许多循环执行。

var arr1 = [{"count":1,"name":"hitler"},{"count":1,"name":"cool"},{"count":1,"name":"cooola"},{"count":1,"name":"cute"},{"count":1,"name":"nyle"},{"count":1,"name":""},{"count":1,"name":"path"},{"count":1,"name":"root"},{"count":1,"name":"sssstag"},{"count":1,"name":"ssssu tag"},{"count":1,"name":"sutag"},{"count":1,"name":"tag2"},{"count":1,"name":"arrogant"},{"count":1,"name":"test01"},{"count":1,"name":"test10"},{"count":1,"name":"uber"},{"count":1,"name":"union"},{"count":1,"name":"assettag"},{"count":1,"name":"wire"}];

function intersect_arrays(a, b) {

    var matches = [];

    for ( var i = 0; i < a.length; i++ ) {
        for ( var e = 0; e < b.length; e++ ) {
            if ( a[i].name === b[e] ) matches.push( b[e] );
        }
    }
    return matches;
}


var arr2 = ["hilter","arrogant","cool","uber"];

var finalArray = intersect_arrays(arr1, arr2);
console.log(finalArray);

有人帮助我更好地实现同样的目标吗？

Answer 1

用

替换内部for循环

var matches = a.filter( function(item){ return b.indexOf( item.name ) > -1 } );

例如

＆＃13;

var arr1 = [{
  "count": 1,
  "name": "hitler"
}, {
  "count": 1,
  "name": "cool"
}, {
  "count": 1,
  "name": "cooola"
}, {
  "count": 1,
  "name": "cute"
}, {
  "count": 1,
  "name": "nyle"
}, {
  "count": 1,
  "name": ""
}, {
  "count": 1,
  "name": "path"
}, {
  "count": 1,
  "name": "root"
}, {
  "count": 1,
  "name": "sssstag"
}, {
  "count": 1,
  "name": "ssssu tag"
}, {
  "count": 1,
  "name": "sutag"
}, {
  "count": 1,
  "name": "tag2"
}, {
  "count": 1,
  "name": "arrogant"
}, {
  "count": 1,
  "name": "test01"
}, {
  "count": 1,
  "name": "test10"
}, {
  "count": 1,
  "name": "uber"
}, {
  "count": 1,
  "name": "union"
}, {
  "count": 1,
  "name": "assettag"
}, {
  "count": 1,
  "name": "wire"
}];

var arr2 = ["hilter", "arrogant", "cool", "uber"];

function intersect_arrays(a, b) {
  var matches = a.filter(function(item) {
    return b.indexOf(item.name) > -1
  });
  matches = matches.map( function(item){ return item.name } );
  return matches;
}

console.log(intersect_arrays(arr1, arr2))

＆＃13;

Answer 2

如果您只想合并数组，请参阅Array.concat（）： http://www.w3schools.com/jsref/jsref_concat_array.asp

所以你的代码是这样的： var mergedArray = arr1.concat（arr2）;

这将把它们组合在一起。如果你想在条件上合并，我认为这不是最好的解决方案。

Answer 3

您可以使用此

替换两个for循环

for ( var i = 0; i < a.length; i++ ) {
    if (b[e].indexOf(a[i].name) != -1) {
        matches.push( b[e] );
    }
}

Answer 4

您可以使用Array.reduce和Array.indexOf更具功能性的方法来生成结果。然而，这与您发布的代码几乎相同，但丑陋的部分已经被抽象掉了。

const arr1 = [
  {"count":1,"name":"hitler"},{"count":1,"name":"cool"}, 
  {"count":1,"name":"cooola"},{"count":1,"name":"cute"},
  {"count":1,"name":"nyle"},{"count":1,"name":""},
  {"count":1,"name":"path"},{"count":1,"name":"root"},
  {"count":1,"name":"sssstag"},{"count":1,"name":"ssssu tag"},
  {"count":1,"name":"sutag"},{"count":1,"name":"tag2"},
  {"count":1,"name":"arrogant"},{"count":1,"name":"test01"},
  {"count":1,"name":"test10"},{"count":1,"name":"uber"},
  {"count":1,"name":"union"},{"count":1,"name":"assettag"},
  {"count":1,"name":"wire"}
];

const arr2 = ["hilter","arrogant","cool","uber"];

const intersect_arrays = function(arr, keys) {
  // reduce the array of objects
  return arr.reduce((acc, x) => {
    // check if the name property is contained in the keys array
    if (~keys.indexOf(x.name)) {
      // add the name to the returned values
      return acc.concat(x.name)
    }
    return acc
  }, [])  
}  

console.log(intersect_arrays(arr1, arr2))

Answer 5

以下是几个选项：

OPTION1 ：

使用 indexOf 来避免第二次循环。

var arr1 = [{"count":1,"name":"hitler"},{"count":1,"name":"cool"},{"count":1,"name":"cooola"},{"count":1,"name":"cute"},{"count":1,"name":"nyle"},{"count":1,"name":""},{"count":1,"name":"path"},{"count":1,"name":"root"},{"count":1,"name":"sssstag"},{"count":1,"name":"ssssu tag"},{"count":1,"name":"sutag"},{"count":1,"name":"tag2"},{"count":1,"name":"arrogant"},{"count":1,"name":"test01"},{"count":1,"name":"test10"},{"count":1,"name":"uber"},{"count":1,"name":"union"},{"count":1,"name":"assettag"},{"count":1,"name":"wire"}];

function intersect_arrays(a, b) {
var matches = [];        
a.forEach(function(item){
  if(b.indexOf(item.name) > -1) {
    matches.push(item.name);
  }
});
return matches;
}


var arr2 = ["hilter", "arrogant", "cool", "uber"];

var finalArray = intersect_arrays(arr1, arr2);

console.log(finalArray);

选项2：

您还可以使用过滤器和地图以更具说明性的方式执行此操作。

var arr1 = [{"count":1,"name":"hitler"},{"count":1,"name":"cool"},{"count":1,"name":"cooola"},{"count":1,"name":"cute"},{"count":1,"name":"nyle"},{"count":1,"name":""},{"count":1,"name":"path"},{"count":1,"name":"root"},{"count":1,"name":"sssstag"},{"count":1,"name":"ssssu tag"},{"count":1,"name":"sutag"},{"count":1,"name":"tag2"},{"count":1,"name":"arrogant"},{"count":1,"name":"test01"},{"count":1,"name":"test10"},{"count":1,"name":"uber"},{"count":1,"name":"union"},{"count":1,"name":"assettag"},{"count":1,"name":"wire"}];

function intersectArrays(a, b) {
return a.filter(function(item){
  return (b.indexOf(item.name) > -1)
});
}


var arr2 = ["hilter", "arrogant", "cool", "uber"];

var finalArray = intersectArrays(arr1, arr2).map(function(item) {
  return item.name;
});

console.log(finalArray);

如何在javascript中将数组1 [对象数组]与数组2进行比较

5 个答案: