Question

我收到缩进错误。任何人都可以帮助我修复它并获得def POST(self): form = web.input(name="a", newname="s", number="d") conn = MySQLdb.connect(host= "localhost", user="root", passwd="", db="testdb") x = conn.cursor() x.execute("SELECT * FROM details WHERE name = '%s'" % (form.name)) conn.commit() items = x.fetchall() for row in items: print row[0], row[1],row[2] print("<table border='1'>") print("<tr>") print("<th>name</th>") print("<th>address</th>") print("<th>number</th>") print("</tr>") print("<tr>") print("<td>{0}</td>".format(row[0])) print("<td>{1}</td>".format(row[1])) print("<td>{2}</td>".format(row[2])) print("</tr>") print("</table>") conn.rollback() conn.close() #return render.index(items) if __name__ == "__main__": app.run()

这是我的代码

 print("</tr>")
 print("</table>")

我在这些行中收到错误

  select  CountryCode, Language, floor(percentage) as speakers 
    from countrylanguage c
    where percentage = (select max(percentage) from countrylanguage c2 where c2.countrycode = c.countrycode group by c2.countrycode)

Answer 1

这是一个非常基本的错误。如果您使用的是sublime text.Please选择所有行。在每行def POST的开头，将有两种模式。一个是'_____'和'.......'。整个模式应该是相似的 'def POST（self）：' 请确保删除此错误。

复制并粘贴此代码：

    def POST(self):
            form = web.input(name="a", newname="s", number="d")
            conn = MySQLdb.connect(host= "localhost", user="root", passwd="", db="testdb")
            x = conn.cursor()
            x.execute("SELECT * FROM details  WHERE name = '%s'" % (form.name))
            conn.commit()
            items = x.fetchall()
            for row in items:
                print row[0], row[1],row[2]
                print("<table border='1'>")
                print("<tr>")
                print("<th>name</th>")
                print("<th>address</th>")
                print("<th>number</th>")
                print("<tr>")
                print("<td>{0}</td>".format(row[0]))
                print("<td>{1}</td>".format(row[1]))
                print("<td>{2}</td>".format(row[2]))
                print("</tr>")
                print("</table>")

                conn.rollback()
                conn.close()
                #return render.index(items)

    if __name__ == "__main__":
        app.run()

感谢。

python中的缩进错误和索引超出范围错误

1 个答案: