Question

我有三列名称：

 projectNo| process | procLeader | procCheker  |     Stuff     |
----------+---------+------------+-------------+---------------+
 16090001 | ANM     | ben        | barry       | bob, bart, bok| 
 16090001 | BLD     | anton      | kirill      | kart, ali     |

我想要的是计算procLeader，procChecker，填充分配给projectNo的列。我设法使用查询计算每列：

SELECT 
    COUNT(procLeader) AS `ld`, 
    COUNT(procChecker) AS `ch`, 
    SUM((LENGTH(stuff) - LENGTH(REPLACE(stuff,",","")) + 1)) AS `st` 
FROM `process` 
WHERE projectNo=16090001;

我得到了

 ld| ch | st |
---+----+----+
  2|   2|   5|

我需要像'总'表

这样的东西

我如何总结这些价值观？或者可能使用其他方法？

Answer 1

SELECT 
COUNT(procLeader) AS `ld`, COUNT(procCheker) AS `ch`, 
SUM((LENGTH(stuff) - LENGTH(REPLACE(stuff,",","")) + 1)) AS `st` ,
(
   COUNT(procLeader) + 
    COUNT(procCheker) +
    SUM((LENGTH(stuff) - LENGTH(REPLACE(stuff,",","")) + 1)) 
 ) As `Total` 
 FROM `process` WHERE projectNo=16090001

如果您有任何疑虑或问题，请告知我们。

Answer 2

使用以下查询，它有效：

SELECT 
COUNT(procLeader) AS `ld`, COUNT(procChecker) AS `ch`, 
SUM((LENGTH(stuff) - LENGTH(REPLACE(stuff,",","")) + 1)) AS `st` ,
(
   COUNT(procLeader) + 
   COUNT(procChecker) +
   SUM((LENGTH(stuff) - LENGTH(REPLACE(stuff,",","")) + 1)) 
) As `Total` 
FROM `process` WHERE projectNo = 16090001

输出：

Id - ch - st - Total
2  - 2  - 5  - 9

Answer 3

不确定我理解问题，但如果你想计算字符，你是否尝试过char_length和concat？

SELECT char_length(concat(procleader, proccheker, REPLACE(stuff,',',''))) FROM process WHERE projectNo=16090001

如何计算三列MySql

3 个答案: