美好的一天。有一个对象类名称和图标的路径。
currentProject = {'current-project': '../../sprites/123.png',
'composition-project': '../../sprites/123.png',
'room': '../../sprites/123.png',
'terms': '../../sprites/123.png',
'documents': '../../sprites/123.png',
'command': '../../sprites/123.png',
'contact': '../../sprites/123.png'}
如何获得结果?
&__current-project:
background-image: url('../../sprites/123.png')
&__room
background-image: url('../../sprites/123.png')
答案 0 :(得分:1)
在手写笔中,使用迭代语法 for< val-name> < expression>
中的[,< key-name>]currentProject = {'current-project': '../../sprites/123.png',
'composition-project': '../../sprites/123.png',
'room': '../../sprites/123.png',
'terms': '../../sprites/123.png',
'documents': '../../sprites/123.png',
'command': '../../sprites/123.png',
'contact': '../../sprites/123.png'}
div
for k, v in currentProject
&_{k}
background-image v
输出应为
div_current-project {
background-image: '../../sprites/123.png';
}
...