嘿我想在ASP.NET C#中删除字符串中的非数字字符
所以即40,595 p.a。
最终会以40595
结束由于
答案 0 :(得分:182)
有很多方法,但这应该做(不知道它是如何用非常大的字符串执行的):
private static string GetNumbers(string input)
{
return new string(input.Where(c => char.IsDigit(c)).ToArray());
}
答案 1 :(得分:43)
感觉非常适合正则表达。
var s = "40,595 p.a.";
var stripped = Regex.Replace(s, "[^0-9]", "");
"[^0-9]"
可以替换为@"\D"
,但我喜欢[^0-9]
的可读性。
答案 2 :(得分:6)
扩展方法将是一种更好的方法:
public static string GetNumbers(this string text)
{
text = text ?? string.Empty;
return new string(text.Where(p => char.IsDigit(p)).ToArray());
}
答案 3 :(得分:5)
使用仅捕获0-9的正则表达式并抛弃其余部分。正则表达式是第一次花费很多的操作。或者做这样的事情:
var sb = new StringBuilder();
var goodChars = "0123456789".ToCharArray();
var input = "40,595";
foreach(var c in input)
{
if(goodChars.IndexOf(c) >= 0)
sb.Append(c);
}
var output = sb.ToString();
我认为这样的东西,虽然我没有编译..
正如Fredrik所说,LINQ也是一个选项
答案 4 :(得分:3)
另一种选择......
private static string RemoveNonNumberDigitsAndCharacters(string text)
{
var numericChars = "0123456789,.".ToCharArray();
return new String(text.Where(c => numericChars.Any(n => n == c)).ToArray());
}
答案 5 :(得分:3)
public static string RemoveNonNumeric(string value) => Regex.Replace(value, "[^0-9]", "");
答案 6 :(得分:0)
嗯,你知道数字是什么:0123456789,对吗?逐个字符地遍历你的字符串;如果字符是数字,则将其粘贴到临时字符串的末尾,否则忽略。可能有其他辅助方法可用于C#字符串,但这是一种适用于所有地方的通用方法。
答案 7 :(得分:0)
以下是使用正则表达式的代码:
string str = "40,595 p.a.";
StringBuilder convert = new StringBuilder();
string pattern = @"\d+";
Regex regex = new Regex(pattern);
MatchCollection matches = regex.Matches(str);
foreach (Match match in matches)
{
convert.Append(match.Groups[0].ToString());
}
int value = Convert.ToInt32(convert.ToString());
答案 8 :(得分:0)
接受的答案很棒,但它不考虑NULL值,因此在大多数情况下都无法使用。
这促使我使用这些辅助方法。第一个答案是OP,而其他人可能对那些想要表现相反的人有用:
/// <summary>
/// Strips out non-numeric characters in string, returning only digits
/// ref.: https://stackoverflow.com/questions/3977497/stripping-out-non-numeric-characters-in-string
/// </summary>
/// <param name="input">the input string</param>
/// <param name="throwExceptionIfNull">if set to TRUE it will throw an exception if the input string is null, otherwise it will return null as well.</param>
/// <returns>the input string numeric part: for example, if input is "XYZ1234A5U6" it will return "123456"</returns>
public static string GetNumbers(string input, bool throwExceptionIfNull = false)
{
return (input == null && !throwExceptionIfNull)
? input
: new string(input.Where(c => char.IsDigit(c)).ToArray());
}
/// <summary>
/// Strips out numeric and special characters in string, returning only letters
/// </summary>
/// <param name="input">the input string</param>
/// <param name="throwExceptionIfNull">if set to TRUE it will throw an exception if the input string is null, otherwise it will return null as well.</param>
/// <returns>the letters contained within the input string: for example, if input is "XYZ1234A5U6~()" it will return "XYZAU"</returns>
public static string GetLetters(string input, bool throwExceptionIfNull = false)
{
return (input == null && !throwExceptionIfNull)
? input
: new string(input.Where(c => char.IsLetter(c)).ToArray());
}
/// <summary>
/// Strips out any non-numeric/non-digit character in string, returning only letters and numbers
/// </summary>
/// <param name="input">the input string</param>
/// <param name="throwExceptionIfNull">if set to TRUE it will throw an exception if the input string is null, otherwise it will return null as well.</param>
/// <returns>the letters contained within the input string: for example, if input is "XYZ1234A5U6~()" it will return "XYZ1234A5U6"</returns>
public static string GetLettersAndNumbers(string input, bool throwExceptionIfNull = false)
{
return (input == null && !throwExceptionIfNull)
? input
: new string(input.Where(c => char.IsLetterOrDigit(c)).ToArray());
}
有关其他信息,请访问我的博客{/ 3}}。
答案 9 :(得分:0)
如果您在VB中工作并在这里结束,则“ .Where”对我来说是一个错误。从这里得到这个:https://forums.asp.net/t/1067058.aspx?Trimming+a+string+to+remove+special+non+numeric+characters
Function ParseDigits(ByVal inputString as String) As String
Dim numberString As String = ""
If inputString = Nothing Then Return numberString
For Each c As Char In inputString.ToCharArray()
If c.IsDigit Then
numberString &= c
End If
Next c
Return numberString
End Function
答案 10 :(得分:-1)
var output = new string(input.Where(char.IsNumber).ToArray());