Question

{"57ecf565817bc3932d8de349": {
  "prices": {

    "2017-07-01": {
      "summer": -1, 
      "winter": -1, 
      "xmas": -1},

    "2017-08-05": {
      "summer": -1, 
      "winter": -1, 
      "xmas": -1}
    }
  }
}

如何编写每个密钥不同的JSON模式（此处：2017-07-01,2017-08-05），因此我无法使用items，例如{{3 （产品架构集）。

这是我的架构：

{
  "type": "object",
  "properties": {
    "57ecf565817bc3932d8de349": {
      "type": "object",
      "properties": {
        "prices": {
          "type": "object",
          "properties": {
            "2017-07-01": {
              "type": "object",
              "properties": {
                "summer": {
                  "type": "integer"
                },
                "winter": {
                  "type": "integer"
                },
                "xmas": {
                  "type": "integer"
                }
              },
              "required": [
                "summer",
                "winter",
                "xmas"
              ]
            },
            "2017-08-05": {
              "type": "object",
              "properties": {
                "summer": {
                  "type": "integer"
                },
                "winter": {
                  "type": "integer"
                },
                "xmas": {
                  "type": "integer"
                }
              },
              "required": [
                "summer",
                "winter",
                "xmas"
              ]
            }
          },
          "required": [
            "2017-07-01",
            "2017-08-05"
          ]
        }
      },
      "required": [
        "prices"
      ]
    }
  },
  "required": [
    "57ecf565817bc3932d8de349"
  ]
}

在我原来的JSON中，我有很多这样的日期：2017-07-01，我想避免重复每个日期的架构。

Answer 1

您可以使用additionalProperties关键字执行此操作。在此示例中，对象中的每个属性都必须针对给定的架构进行验证。

{
  "type": "object",
  "additionalProperties": {
    "type": "object",
    "properties": {
      "summer": { "type": "integer" },
      "winter": { "type": "integer" },
      "xmas": { "type": "integer" }
    },
    "required": ["summer", "winter", "xmas"]
  }
}

Answer 2

架构定义静态数据结构。

因此，您无法为动态数据结构编写架构。

这不仅适用于JSON，而且适用于XSD / SQL / protobuf等。模式是一个严格的物理蓝图，用于显示某些内容。

您最好为数据定义静态类型，并执行以下操作：

{
    "type":"object",
    "properties":{
        "resource":{
            "type":"object",
            "properties":{
                "hash":{
                    "type":"string"
                },
                "prices":{
                    "type":"array",
                    "items":{
                        "$ref":"#/definitions/price"
                    },
                    "minItems":1
                }
            },
            "required":[
                "hash",
                "prices"
            ]
        }
    },
    "definitions":{
        "price":{
            "type":"object",
            "properties":{
                "date":{
                    "type":"string"
                },
                "summer":{
                    "type":"integer"
                },
                "winter":{
                    "type":"integer"
                },
                "xmas":{
                    "type":"integer"
                }
            },
            "required":[
                "date",
                "summer",
                "winter",
                "xmas"
            ]
        }
    }
}

这将允许您拥有您的实例：

{
    "resource":{
        "hash":"57ecf565817bc3932d8de349",
        "prices":[
            {
                "date":"2017-07-01",
                "summer":-1,
                "winter":-1,
                "xmas":-1
            },
            {
                "date":"2017-08-05",
                "summer":-1,
                "winter":-1,
                "xmas":-1
            }
        ]
    }
}

Answer 3

使用patternProperties

https://json-schema.org/understanding-json-schema/reference/object.html#pattern-properties

类似

{
  "type": "object",
  "patternProperties": {
    "^\d{4}-\d{2}-\d{2}": { 
      "type": "object",
      "properties": {
         "summer": {
            "type": "integer"
         },
         "winter": {
           "type": "integer"
           etc...

JSON模式，其中键具有不同的名称

3 个答案: