Question

我正在制作一个Hangman的迷你小游戏。用户有10次猜测的机会，但只有5次生命。

该应用程序可以运行，但会在第5次生命之后继续，即使我希望它会让玩家退出该循环。

可实例化的类（Hangman.java）正常运行。

秘密词是“julie”，如可实例化的类中所述。

我的App类：

    import javax.swing.JOptionPane;

    public class HangmanApp {

    public static void main(String args[]) {
    String input, secret, result, playAgain;
    char guess;
    int i, j, k, lives;

    Hangman myHangman = new Hangman();

    do{
        JOptionPane.showMessageDialog(null, "Hello, welcome to Hangman! You have 10 chances but only 5 lives! Best of luck");

        lives = 5;

        for (j = 10; j > 0; j--) {

            while (lives >= 0){
                input = JOptionPane.showInputDialog(null, "Please enter a letter");
                guess = input.charAt(0);

                //process
                myHangman.setGuess(guess);
                myHangman.compute();
                result = myHangman.getResult();

                if ((input.charAt(0) == 'j') || (input.charAt(0) == 'u') || (input.charAt(0) == 'l') || (input.charAt(0) == 'i') || (input.charAt(0) == 'e')) {
                    JOptionPane.showMessageDialog(null, "That letter is in the word! Current correct letters:  " + result + ".");
                } else {
                    lives--;
                    JOptionPane.showMessageDialog(null, "Sorry, that letter is not there. Current correct letters:  " + result + ".");
                }

                //output
                //JOptionPane.showMessageDialog(null, "Current correct letters:  " + result);

            };
            lives = -1;
        }
        result = myHangman.getResult();
        secret = myHangman.getSecret();

        if (secret.equals(result)) {
            JOptionPane.showMessageDialog(null, "Congratulations, you got it!! The word was " + secret + ".");
        } else {
            JOptionPane.showMessageDialog(null, "Sorry, you didn't get it, better look next time! The word was " + secret + ".");
        }

        playAgain = JOptionPane.showInputDialog("Do you want to play again? yes/no");

    }while (playAgain.equals("yes"));
}

}

Answer 1

请尝试以下更改：

while (lives > 0){

你从5开始，然后下降到4 3 2 1和0.随着改变，这将停止在0

Answer 2

    // don't need two nested cycles, you can do it in a single one
    // The cycle exits if any one of the conditions fail
    //  max attempts exhausted or all the lives are lost
    // -------------------v        v------------------------             
    for (j = 10, lives=5; j > 0 && lives > 0 ; j--) {
       // -------------------------------------^
       // j - the number of attempt is decremented for each trial,
       // no matter if successful or not

       //... the rest of cycle logic, which will decrement the lives
       //  only in cases of unsuccessful attempts

    }

Java：Hangman游戏，有10次机会，但只有5次生命

2 个答案: