Question

这是打印出来的代码。当输入0时，用户程序输入的一组数字中的素数停止。变量计数器未更新，结果仍为0.如何更新计数器的值？

class Prog4 {

    public static void main(String a[]){
        int c=0;
        //int[] array=new int[10];
        int counter=0;
        Scanner b=new Scanner(System.in);
        System.out.println("Enter the numbers");
        c=b.nextInt();
        while(c!=0){
            boolean y=false;
            for(int j=2;j<c;j++){
                if(c%j==0)
                    y=true;
                }
            if(y=false){
                counter++;
                //array[counter-1]=c;
                }       
            c=b.nextInt();
            }
        System.out.println("No. of prime numbers entered :" + counter);
        //System.out.println("The prime numbers are : ");
        //for(int x:array) 
            //System.out.println(x);    
    }

}

Answer 1

做到：

public class Prog4 {

    public static void main(String[] args) {
        int c = 0;
        int[] array = new int[10];
        int counter = 0;
        System.out.println("Enter the numbers:");
        do {
            Scanner b = new Scanner(System.in);
            c = b.nextInt();
            boolean y = false;
            for (int j = 2; j < c; j++) {
                if (c % j == 0)
                    y = true;
            }
            if (y == false && c != 0) {
                counter++;
                array[counter - 1] = c;
            }
        } while (c != 0);
        System.out.println("No. of prime numbers entered:" + counter);
        System.out.println("The prime numbers are: ");
        for (int i = 0; i < counter; i++)
            System.out.println(array[i]);
    }

}

输入：

Enter the numbers:
1
2
3
4
5
6
7
8
9
10
11
0

输出：

No. of prime numbers entered: 6
The prime numbers are: 
1
2
3
5
7
11

基本上，这是错误的：

扫描仪在循环之外;
你正在使用＆＃34; if（y = false）＆＃34;而不是＆＃34; if（y == false）＆＃34;。

更改后，如何使计数器变量保持其值？

1 个答案: