Question

我开始生成一个包含从这个（现在）月开始的12个月日历的数组。这是针对特定应用程序的，需要特殊代码，因此我无法使用日历库。

这是我的代码：

header('Content-type: text/plain');

$Cal1 = array();

$now = new fTimestamp('now');
$now = $now->modify('Y-m-1 00:00:00');

for ( $i = 0; $i < 12; $i++ ) {
 if ( $i > 1 ) {
  $then = $now->adjust("+$i months");
 }
 elseif ( $i == 1 ) {
  $then = $now->adjust("+1 month");
 }
 else {
  $then = $now;
 }
 $thisMonth = $then->format('F');
 $Cal1[$thisMonth] = array();
 $thisMonthDays = $then->format('t');
 for ( $j = 0; $j < $thisMonthDays; $j++ ) {
  if ( $i > 1 ) {
   $then = $then->adjust("+$i days");
  }
  elseif ( $i == 1 ) {
   $then = $then->adjust("+1 day");
  }
  $thisDate = $then->format('j');
  $thisDay = $then->format('l');
  $Cal1[$thisMonth][$thisDate] = $thisDay;
 }
}

var_dump($Cal1);

这应该生成一个形式的数组：

array {
    ["Month_Name"] => array {
        [Day_Number] => "Day_Name"
        etc...
    }
    etc...
}

脚本输出正确的月数，但不是正确的天数......完全转储非常冗长，所以我只发布10月，2月和3月：

array(12) {
  ["October"]=>
  array(1) {
    [1]=>
    string(6) "Friday"
  }
  ["February"]=>
  array(22) {
    [5]=>
    string(8) "Saturday"
    [9]=>
    string(9) "Wednesday"
    [13]=>
    string(6) "Sunday"
    [17]=>
    string(8) "Thursday"
    [21]=>
    string(6) "Monday"
    [25]=>
    string(6) "Friday"
    [1]=>
    string(7) "Tuesday"
    [29]=>
    string(7) "Tuesday"
    [2]=>
    string(8) "Saturday"
    [6]=>
    string(9) "Wednesday"
    [10]=>
    string(6) "Sunday"
    [14]=>
    string(8) "Thursday"
    [18]=>
    string(6) "Monday"
    [22]=>
    string(6) "Friday"
    [26]=>
    string(7) "Tuesday"
    [30]=>
    string(8) "Saturday"
    [4]=>
    string(9) "Wednesday"
    [8]=>
    string(6) "Sunday"
    [12]=>
    string(8) "Thursday"
    [16]=>
    string(6) "Monday"
    [20]=>
    string(6) "Friday"
    [24]=>
    string(7) "Tuesday"
  }
  ["March"]=>
  array(19) {
    [6]=>
    string(6) "Sunday"
    [11]=>
    string(6) "Friday"
    [16]=>
    string(9) "Wednesday"
    [21]=>
    string(6) "Monday"
    [26]=>
    string(8) "Saturday"
    [31]=>
    string(8) "Thursday"
    [5]=>
    string(8) "Thursday"
    [10]=>
    string(7) "Tuesday"
    [15]=>
    string(6) "Sunday"
    [20]=>
    string(6) "Friday"
    [25]=>
    string(9) "Wednesday"
    [30]=>
    string(6) "Monday"
    [4]=>
    string(6) "Monday"
    [9]=>
    string(8) "Saturday"
    [14]=>
    string(8) "Thursday"
    [19]=>
    string(7) "Tuesday"
    [24]=>
    string(6) "Sunday"
    [29]=>
    string(6) "Friday"
    [3]=>
    string(9) "Wednesday"
  }

现在，怎么回事？

Answer 1

不能直接回答你的问题，但我会这样做的更简单：

$cursor = mktime(0, 0, 0, date('m'), 1);
$end = strtotime('+1 year', $cursor);

$out = array();

while ($cursor < $end) {
    $out[date('F', $cursor)][date('j', $cursor)] = date('l', $cursor);
    $cursor = strtotime('+1 day', $cursor);
}

var_dump($out);

要直接回答你的问题，你总是会以越来越大的数字相对于自己调整$then，因此你会跳过几天并且得到时髦的数字。

 for ( $j = 1; $j < $thisMonthDays; $j++ ) {
     $then = $then->adjust("+$i days");
 }

$then是第1个，你加1（第一次迭代）
$then是第二个，你加2（第二次迭代）
$then是第4个，你加3个
$then是第7个，你加4个
etc pp。

日历生成奇怪失败

1 个答案: