我的sql文件内容是：
CREATE EXTERNAL TABlE unLock(logTime TIMESTAMP, ystID STRING,deviceID STRING)
ROW FORMAT SERDE 'org.apache.hadoop.hive.contrib.serde2.MultiDelimitSerDe'
WITH SERDEPROPERTIES ("field.delim"="$$")
STORED AS TEXTFILE
LOCATION concat(hdfs://hadoop1:9000/logHive/unLock/,${hiveconf:logdir});
我的shell脚本文件内容是：
hive -hiveconf logdir="$(date +'%Y/%m/%d/')" -f /home/yst/create.sql
当我在cmd中运行shell文件时，错误是：
FAILED: ParseException line 7:9 mismatched input 'concat' expecting StringLiteral near 'LOCATION' in table location specification
我不知道为什么。我只想要hive表的位置是当天的文件。
答案 0 :(得分：1)
尚未测试，但这可能有效：
new Thread(new Runnable() {
@Override
public void run() {
try {
//URL url = new URL("http://192.168.2.5:5213/controller/moodoff/notifications/9681578989");
URL url = new URL("http://echo.jsontest.com/key/value/one/two");
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
InputStream is = urlConnection.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
int data = isr.read();
StringBuilder response = new StringBuilder("");
if(data!=-1){
response.append((char)data);
data = isr.read();
}
Log.i("TAG","Response:="+response.toString());
//allNotifications.setText("Hi:"+response.toString());
}catch(Exception ee){allNotifications.setText(ee.getMessage());ee.printStackTrace();}
}
}).start();