我编写了代码来模拟缓存的工作。
在这个模型中,我尝试实现FIFO算法,它允许我们删除最后一个未使用的元素(数据,值,等等)。
我写了一个特殊的函数,它给我一个带有数字的列表 o (这些数字是内存中的地址)。
q=Queue.Queue(800)# Cache - memory. This is a queue which is more likely help me to simulate FIFO-algorithm
QW=[] # External memory
l=raw_input("Enter a desire operation:")#I enter my operation.
for i in range(len(o)):
time.sleep(0.4)
u = time.time()
k=o.pop(0) #o - is the list with numbers (these numbers are addresses in memory). Here I get each address through pop.
while l=='read': #If operation is "read" then i need to get my adress from q (cache-mem) or from QW (Is the external memory) and put it in q - (is the Cache-memory).
if k not in q:
if j in QW and k==j:
q.put(j)
else:
q.get(k)
while l=='record':#If operation is "record" then i need to write (append to QW) an address in QW or q, but only if the same address have existed already in QW or q.
if k not in q:
QW.append(k)
print QW
else:
q.put(k)
print q.get()
但我收到错误:
TypeError: argument of type 'instance' is not iterable at line
if k not in q
答案 0 :(得分:0)
你不能用我想的队列那样做,而是使用collections.dequeue,它们几乎相似,而集合有快速append(),pop()。您可以将代码的第一行更改为q=collections.deque([],800)
,而不是q.put,q .get使用q.append
,q.popleft()
。