我在数据库中有四个表：
表1： Employee_Details
-----------------------------------------------------------------------
| Employee ID | Name | Department |DateofJoining |
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| | | | |
| e1 | name1 | d1 | date1 |
| e2 | name2 | d2 | date2 |
| e3 | name3 | d3 | date3 |
-----------------------------------------------------------------------
表2： Employee_SkillSet
----------------------------------------------------------------------------
| EmployeeID | SkillId | SkillName | SkillExperience | SkillRating |
----------------------------------------------------------------------------
| | | | | |
| e1 | s1 | skill1 | 11| 11|
| e1 | s2 | skill2 | 12| 12|
| e1 | s3 | skill3 | 13| 13|
| e2 | s1 | skill1 | 21| 21|
| e2 | s2 | skill2 | 22| 22|
| e2 | s3 | skill3 | 23| 23|
----------------------------------------------------------------------------
表3： Employee_Certifications
-----------------------------------------------------------------------
| EmployeeID | CertificationID | Name |
-----------------------------------------------------------------------
| | | |
| e1 | c1 | cname1 |
| e1 | c2 | cname2 |
| e2 | c3 | cname3 |
-----------------------------------------------------------------------
表4： Other_Details
----------------------------------------------------------------------------
| EmployeeId | TotalExp | Qualification | Specialization |
----------------------------------------------------------------------------
| | | | |
| e1 | 1 | q1 | abc |
| e2 | 2 | q2 | xyz |
----------------------------------------------------------------------------
现在，必须查询上述四个表以获得如下输出：
+------------+-------+-------------+---------------+---------+----------------+----------------+------------+----------------+--------+--------------+------------------+
| EmployeeID | Name | Department | Qualification | Tot_Exp | Specialization | Certifications | Skill1_Exp | Skill1_Rating | ……………… | Skill100_Exp | Skill100_Rating |
+------------+-------+-------------+---------------+---------+----------------+----------------+------------+----------------+--------+--------------+------------------+
| | | | | | | | | | | | |
| e1 | name1 | d1 | q1 | 1 | spec1 | c1,c2 | 11 | 11 | ……………. | ………………… | ……………………… |
| e2 | name2 | d2 | q2 | 2 | spec2 | c3 | 21 | 21 | ……………. | ………………… | ……………………… |
+------------+-------+-------------+---------------+---------+----------------+----------------+------------+----------------+--------+--------------+------------------+
到目前为止，我已经能够在表2-Employee_SkillSet上执行查询（使用动态SQL），类似于下面的内容：
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| EmpId | S1_Exp | S1_Rating | S2_Exp | S2_Rating | S3_Exp | S3_Rating |....
----------------------------------------------------------------------------
| | | | | | | |
| e1 | 11 | 11 | 12 | 12 | 13 | 13 |....
| e2 | 21 | 21 | 22 | 22 | 23 | 23 |....
| e3 | 31 | 31 | 32 | 32 | 33 | 33 |....
----------------------------------------------------------------------------
P.S. S is for Skill which I abbreviated over here to conserve space
我的问题是，我如何逐行加入其他三个表来获得所需的输出？
我应该指出，我很喜欢加入，转动/转移，交叉应用以及介于两者之间的所有内容，所以即使答案非常简单，我似乎无法弄明白。
修改
创作脚本：
CREATE TABLE Employee_Details (
[Employee ID] nvarchar(2),
[Name] nvarchar(10),
Department nvarchar(2),
DateofJoining nvarchar(5)
)
INSERT INTO Employee_Details VALUES
('e1', 'name1', 'd1', 'date1'),
('e2', 'name2', 'd2', 'date2'),
('e3', 'name3', 'd3', 'date3')
CREATE TABLE Employee_SkillSet (
EmployeeID nvarchar(2),
SkillId nvarchar(2),
SkillName nvarchar(10),
SkillExperience int,
SkillRating int
)
INSERT INTO Employee_SkillSet VALUES
('e1', 's1', 'skill1', 11, 11),
('e1', 's2', 'skill2', 12, 12),
('e1', 's3', 'skill3', 13, 13),
('e2', 's1', 'skill1', 21, 21),
('e2', 's2', 'skill2', 22, 22),
('e2', 's3', 'skill3', 23, 23)
CREATE TABLE Employee_Certifications (
EmployeeID nvarchar(2),
CertificationID nvarchar(2),
[Name] nvarchar(10)
)
INSERT INTO Employee_Certifications VALUES
('e1', 'c1', 'cname1'),
('e1', 'c2', 'cname2'),
('e2', 'c3', 'cname3')
CREATE TABLE Other_Details (
EmployeeId nvarchar(2),
TotalExp int,
Qualification nvarchar(2),
Specialization nvarchar(100)
)
INSERT INTO Other_Details VALUES
('e1', 1, 'q1', 'abc'),
('e2', 2, 'q2', 'xyz')
创建脚本：
答案 0 :(得分：0)
您可以使用以下功能代替使用动态SQL技能：
SELECT ed.EmployeeID AS EmpID,
ss1.SkillExperience AS S1_Exp,
ss1.SkillRating AS S1_Rating,
ss2.SkillExperience AS S2_Exp,
ss2.SkillRating AS S2_Rating,
ss3.SkillExperience AS S3_Exp,
ss3.SkillRating AS S3_Rating
FROM Employee_Details ed
INNER JOIN Employee_SkillSet ss1 ON ed.EmployeeID = ss1.EmployeeID AND ss1.SkillName = 'skill1'
INNER JOIN Employee_SkillSet ss2 ON ed.EmployeeID = ss2.EmployeeID AND ss2.SkillName = 'skill2'
INNER JOIN Employee_SkillSet ss3 ON ed.EmployeeID = ss3.EmployeeID AND ss3.SkillName = 'skill2'
现在完成它
WITH Certifications AS
(
SELECT EmployeeId
,STUFF((SELECT ', ' + CAST(Name AS VARCHAR(10)) [text()]
FROM Employee_Certifications
WHERE EmployeeId = c.EmployeeId
FOR XML PATH(''), TYPE)
.value('.','NVARCHAR(MAX)'),1,2,' ') Certifications
FROM Employee_Certifications c
GROUP BY EmployeeId
)
,Skills AS
(
SELECT ed.EmployeeID AS EmpID,
ss1.SkillExperience AS S1_Exp,
ss1.SkillRating AS S1_Rating,
ss2.SkillExperience AS S2_Exp,
ss2.SkillRating AS S2_Rating,
ss3.SkillExperience AS S3_Exp,
ss3.SkillRating AS S3_Rating
FROM Employee_Details ed
INNER JOIN Employee_SkillSet ss1 ON ed.EmployeeID = ss1.EmployeeID AND ss1.SkillName = 'skill1'
INNER JOIN Employee_SkillSet ss2 ON ed.EmployeeID = ss2.EmployeeID AND ss2.SkillName = 'skill2'
INNER JOIN Employee_SkillSet ss3 ON ed.EmployeeID = ss3.EmployeeID AND ss3.SkillName = 'skill2'
)
SELECT ed.EmployeeID,
ed.Name,
ed.Department,
od.Qualification,
od.TotalExp,
od.Specialization,
c.Certifications,
s.S1_Exp,
s.S1_Rating,
s.S2_Exp,
s.S2_Rating,
s.S3_Exp,
s.S3_Rating
FROM Employee_Details ed
LEFT JOIN Other_Details od ON od.EmployeeId = ed.EmployeeId
LEFT JOIN Certifications c ON c.EmployeeID = ed.EmployeeID
LEFT JOIN Skills s ON s.EmpID = ed.EmployeeID
答案 1 :(得分：0)
Select TBl1.[EmployeeID],Tbl1.Name,Tbl1.Department,TBl1.Qualification, TBl1.TotalExp ,TBl1.Specialization,TBl1.[Certifications]
,Skill1_Exp,Skill1_Rating
,Skill2_Exp,Skill2_Rating
,Skill3_Exp,Skill3_Rating
From
(
Select TBl1.[EmployeeID],Tbl1.Name,Tbl1.Department,Tbl4.Qualification, Tbl4.TotalExp ,Tbl4.Specialization,Tbl3.[Certifications]
From Employee_Details Tbl1 Inner Join Employee_SkillSet Tbl2
On TBl1.[EmployeeID]=TBl2.[EmployeeID]
Inner Join
(
SELECT Dtl.[EmployeeID],
STUFF(( SELECT ',' + Cer.CertificationID AS [text()]
FROM Employee_Certifications Cer
WHERE
Cer.[EmployeeID] = Dtl.[EmployeeID]
FOR XML PATH('')
), 1, 1, '' )
AS [Certifications]
FROM Employee_Details Dtl
) as Tbl3
On Tbl1.[EmployeeID]=Tbl3.[EmployeeID]
Inner Join Other_Details as Tbl4
On Tbl1.[EmployeeID]=Tbl4.[EmployeeID]
Group by TBl1.[EmployeeID],Tbl1.Name,Tbl1.Department,Tbl4.Qualification, Tbl4.TotalExp ,Tbl4.Specialization,Tbl3.[Certifications]
)as Tbl1
Inner Join
(
Select Tbl1.[EmployeeID],Tbl1.skill1 as Skill1_Exp,Tbl2.skill1 as Skill1_Rating
,Tbl1.skill2 as Skill2_Exp,Tbl2.skill2 as Skill2_Rating
,Tbl1.skill3 as Skill3_Exp,Tbl2.skill3 as Skill3_Rating
From
(
Select *
from (seLECT [employeeID],SKILLNAME,SkillExperience FROM Employee_SkillSet )P
PIVOT
(max(SkillExperience )
FOR SkillName IN([skill1], [skill2],[skill3])
) AS PivotSales
)as Tbl1
Inner Join
(
Select *
from (seLECT [employeeID],SKILLNAME,SKILLRATING FROM Employee_SkillSet )P
PIVOT
(
max(SkillRating)
FOR SkillName IN([skill1], [skill2],[skill3])
) AS PivotSales
)as Tbl2
On Tbl1.[EmployeeID]=Tbl2.[EmployeeID]
) as Tbl2
On Tbl1.[EmployeeID]=Tbl2.[EmployeeID]
答案 2 :(得分：0)
您可以使用：
我的解决方案如下：
DECLARE @col nvarchar(max),
@sql nvarchar(max)
SELECT @col = (
SELECT DISTINCT ','+QUOTENAME(SkillName + STUFF([name],1,5,'_'))
FROM Employee_SkillSet es
CROSS JOIN sys.columns sc
WHERE sc.[object_id] = OBJECT_ID(N'Employee_SkillSet')
AND sc.column_id > 3
FOR XML PATH('')
)
--That will generate the string:
--,[skill1_Experience],[skill1_Rating],[skill2_Experience],[skill2_Rating]...[skillN_Experience],[skillN_Rating]
SELECT @sql= N'
SELECT ed.EmployeeID,
ed.[Name],
ed.Department,
STUFF((
SELECT '',''+Qualification
FROM Other_Details
WHERE ed.EmployeeID = EmployeeID
FOR XML PATH('''')
),1,1,'''') as Qualification,
STUFF((
SELECT '',''+CAST(TotalExp as nvarchar(10))
FROM Other_Details
WHERE ed.EmployeeID = EmployeeID
FOR XML PATH('''')
),1,1,'''') as TotalExp,
STUFF((
SELECT '',''+Specialization
FROM Other_Details
WHERE ed.EmployeeID = EmployeeID
FOR XML PATH('''')
),1,1,'''') as Specialization,
STUFF((
SELECT '',''+CertificationID
FROM Employee_Certifications
WHERE ed.EmployeeID = EmployeeID
FOR XML PATH('''')
),1,1,'''') as Certification'+@col+'
FROM Employee_Details ed
LEFT JOIN (
SELECT *
FROM (
SELECT EmployeeID,
SkillName + STUFF(Skills,1,5,''_'') as [Columns],
[Values]
FROM (
SELECT *
FROM Employee_SkillSet
) as es
UNPIVOT (
[Values] FOR Skills IN (SkillExperience,SkillRating)
) unp
) as s
PIVOT (
MAX([Values]) FOR [Columns] IN ('+STUFF(@col,1,1,'')+')
) pvt
) as f
ON f.EmployeeID = ed.EmployeeID'
EXEC sp_executesql @sql
输出：
EmployeeID Name Department Qualification TotalExp Specialization Certification skill1_Experience skill1_Rating skill2_Experience skill2_Rating skill3_Experience skill3_Rating
e1 name1 d1 q1 1 abc c1,c2 11 11 12 12 13 13
e2 name2 d2 q2 2 xyz c3 21 21 22 22 23 23
e3 name3 d3 NULL NULL NULL NULL NULL NULL NULL NULL NULL NULL
注意：我在UNPIVOT部分中使用SkillExperience,SkillRating，如果有更多技能属性 - 那么您可以再使用一个变量@col来传递逗号分隔值。< / p>