将numMatches设置为userValues(具有NUM_VALS个元素)中等于matchValue的元素数。例如:如果matchValue = 2且userValues = {2,2,1,2},则numMatches = 3.
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
**/* Your solution goes here */**
numMatches = 0;
for(i = 0; i < NUM_VALS; ++i) {
if(userValues[i] == matchValue)
numMatches = i;
}
System.out.println("matchValue: " + matchValue + ", numMatches: " + numMatches);
return;
}
}
我的解决方案存在一些我无法弄清楚的错误。
测试matchValue = 0,
userValues = {0,0,0,0,0}
预期价值:5
您的价值:4&lt;&lt;&lt;这是我出错的地方。
答案 0 :(得分:2)
for(i = 0; i < NUM_VALS; ++i) {
if(userValues[i] == matchValue) {
//numMatches = i; //WRONG
numMatches++; //Correct
}
}
此块不正确,您将numMatches分配给数组的索引值,而应该是如果numMatches的匹配增量值为1,则应该是这样。
答案 1 :(得分:1)
numMatches++
这是您在for循环中需要做的而不是numMatches = i;
答案 2 :(得分:0)
std::vector