我正在尝试使用php,我真的很陌生。
我创建了一个页面(使用php代码)将信息发送到数据库,一个页面显示数据库中的信息。
我的问题是:假设我要输入10个信息,但我只显示其中的5个,如何显示其余信息点击每行按钮?
我是否必须为按钮指定值?我无法理解如何将按钮与行相关联。
基本上对于每一行,我想显示该特定行的其余信息,点击该特定按钮。
任何帮助都会适用。感谢
-----在db中插入信息的脚本-----
<?php
$name = mysqli_real_escape_string($link, $_POST['name']);
$mail = mysqli_real_escape_string($link, $_POST['mail']);
$number = mysqli_real_escape_string($link, $_POST['number']);
$device = mysqli_real_escape_string($link, $_POST['device']);
$model = mysqli_real_escape_string($link, $_POST['model']);
$problem = mysqli_real_escape_string($link, $_POST['problem']);
$sql = "INSERT INTO cj (name, mail, number, device, model, problem) VALUES ('$name', '$mail', '$number', '$device', '$model', '$problem')";
$result = mysqli_query($link, $sql);
// if query fails stop script and echo error
if( $result === false)
{echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
exit;
}
header("location:add-customer.php?message=A job and customer has been added to the database");
exit;
echo "You'll never see this";
?>
-----------页面显示信息------
<?php
$sql = "SELECT * from "database name"";
echo "
<table class='table'>
<thead>
<tr>";
/* Get field information for all columns */
echo "<form action='' method=post>";
echo "<tr class='info'>
<input type=hidden name=hidden value=" . $row['id'] . ">
<td>" . $row['id'] . "</td>
<td>" . $row['device'] . "</td>
<td>" . $row['model'] . "</td>
<td>" . $row['problem'] . "</td>
<td>
</td>
<td>
<a class='btn btn-primary btn-sm' data-toggle='modal' data-target='#myModal' value= " . $row['id'] . " > Info</a></form></td>
</tr>";
echo "</form>";
}
echo "
</tbody>
</table>";
?>
<div class="container">
<!-- Trigger the modal with a button -->
<!-- Modal -->
<div class="modal fade" id="myModal" role="dialog">
<div class="modal-dialog modal-lg">
<!-- Modal content-->
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Customer Information</h4>
</div>
<div class="modal-body">
<?php
include("../includes/connection.php");
if ($link->connect_errno > 0) {
die('Unable to connect to database [' . $link->connect_error . ']');
}
$sql = "SELECT name,mail,number from databasename WHERE **???**;
if (!$result = $link->query($sql)) {
die('There was an error running the query [' . $link->error . ']');
}
echo "
<table class='table'>
<thead>
<tr>";
/* Get field information for all columns */
while ($finfo = $result->fetch_field()) {
echo "
<th>" . $finfo->name . "</th>";
}
echo "
</tr>
</thead>
<tbody>";
while ($row = $result->fetch_assoc()) {
echo "<tr class='info'>
<td>" . $row['name'] . "</td>
<td>" . $row['mail'] . "</td>
<td>" . $row['number'] . "</td>
</tr>";
...
答案 0 :(得分:0)
连接到数据库并使用PHP获取所有10个信息。但只显示5个信息。在那里放一个按钮,并使用Javascript或Jquery显示其他行。 (Onclick事件)
答案 1 :(得分:0)
我找到了一个使用ajax的解决方案:
这里是代码:( ajax调用第三个解决我问题的php页面)
<script>
$(document).ready(function(){
$('.get_info').click(function(){
var job_id = $(this).parent().siblings('input[name=hidden]').val();
$.ajax({
url: 'THIRDPAGE.php',
data: 'job_id=' + job_id,
type: 'POST',
success: function(data){
// console.log(data);
$('.info_data').html(data);
}
});
});
});
</script>
对于来到这里的人来说只是评论,我可以更好地解释我做了什么。