我正在尝试以POSIXct格式删除一小时内的秒数:
#"2016-04-02 10:33:45 COT" "2016-04-02 22:19:24 COT"
#"2016-04-09 17:47:13 COT" "2016-04-13 16:56:23 COT"
x <- structure(c(1459589625, 1459631964, 1460220433, 1460562983),
class = c("POSIXct", "POSIXt"), tzone = "")
我正在尝试这个,但我没有看到结果:
y <- as.POSIXct(x, format = "%d/%m/%Y %H:%M")
答案 0 :(得分:3)
不,你给的as.POSIXct
格式错误......
使用格式
怎么样?datetimes = as.POSIXct(c("2016-04-02 10:33:45 COT", "2016-04-02 22:19:24 COT" ,"2016-04-09 17:47:13 COT", "2016-04-13 16:56:23 COT")
format(datetimes,format='%Y%m%d %H:%M')
[1] "20160402 10:33" "20160402 22:19" "20160409 17:47" "20160413 16:56"
答案 1 :(得分:2)
你可以使用round.POSIXt:
round(Sys.time(), units = "mins")
#"2017-01-30 11:20:00 CET"
答案 2 :(得分:1)
这就是你所拥有的:
x <- structure(c(1459589625, 1459631964, 1460220433, 1460562983),
class = c("POSIXct", "POSIXt"), tzone = "")
这就是你想要的:
x <- format(as.POSIXct(x), "%d-%m-%Y %H:%M")
x
[1] "02-04-2016 15:03" "03-04-2016 02:49" "09-04-2016 22:17" "13-04-2016 21:26"
答案 3 :(得分:0)
如果您想将日期分为几分钟,您可以执行此操作:
x <- as.POSIXlt(c("2016-04-02 10:33:45 COT"))
res <-as.POSIXlt(floor(as.double(x) / 60) * 60, origin = '1970-01-01')
res
# "2016-04-02 10:33:00 BST"
答案 4 :(得分:0)
只需使用子字符串:
datetimes <- c("2016-04-02 10:33:45 COT", "2016-04-02 22:19:24 COT" ,
"2016-04-09 17:47:13 COT", "2016-04-13 16:56:23 COT")
as.POSIXct(substring(datetimes, 1, nchar(datetimes[1])-7))
#[1] "2016-04-02 10:33:00 IST" "2016-04-02 22:19:00 IST"
# "2016-04-09 17:47:00 IST" "2016-04-13 16:56:00 IST"
# without timezone
format(substring(datetimes, 1, nchar(datetimes[1])-7),
format='%Y-%m-%d %H:%M:%S', usetz = FALSE)
#[1] "2016-04-02 10:33" "2016-04-02 22:19" "2016-04-09 17:47" "2016-04-13 16:56"