Question

我有一个MySQL数据库，我将URL存储到8个视频中。我想知道的是在滑块中随机显示它们。它一直工作到现在为止，除了视频不是随机的，但总是相同的，这意味着视频是从数据库中随机挑选的，但每次刷新页面时，它都是视频数量的8倍1，下次刷新是8次等8次。

<?php
$mysqli = new mysqli("####", "####", "###", "clearchannel");
if ($mysqli->connect_errno) {
     echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}                      

$res = $mysqli->query("SELECT EmbedURL FROM Videos where location_id='2' ORDER BY RAND() LIMIT 3");
$vid = $res->fetch_assoc();
?>  
                        <ul class="bxslider">
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                            <li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
                        </ul>

Answer 1

你需要在结果上加上：

<ul class="bxslider">
<?php
while($vid = $res->fetch_assoc()){ ?>
<li><iframe src="<?php echo $vid['EmbedURL']; ?>" frameborder="0" autoplay="0" allowfullscreen></iframe></li>
<?php } ?>
</ul>

Answer 2

使用这个新代码更改您的代码：

第一。如果你想要8个不同的视频，你可以将你的结果限制为3个网址，ORDER BY RAND() LIMIT 3"将其更改为8

<?php
$mysqli = new mysqli("####", "####", "###", "clearchannel");
if ($mysqli->connect_errno) {
echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
      }                      

$res = $mysqli->query("SELECT EmbedURL FROM Videos where location_id='2' ORDER BY RAND() LIMIT 8");

 echo'<ul class="bxslider">';

while($url = $res->fetch_assoc()){
echo '<li><iframe src="'.$vid['EmbedURL'].'" frameborder="0" autoplay="0" allowfullscreen></iframe></li>'; 
}?>
                    </ul>

编辑：最后缺少}。

随机视频通过MySQL

2 个答案: