Question

我需要在c中将浮点csv转换为2D数组。已经看过一篇文章（Import CSV elements into a 2D array in C），它解释了转换为整数数组。可以帮助修改这段代码或者我可以用来将csv转换为浮点2D数组的新方法例如：我的csv包含值0.018869,0.015863,0.044758,0.027318,0.049394,0.040823，.....并且是4400 * 500值csv。所以我需要使用一个4400 * 500的大数组来包含所有这些值。

提前致谢

Answer 1

查看libcsv，这是一个用ANSI C89编写的CSV库。但请注意，libcsv是根据LGPL许可的。

Answer 2

使用atof（）将字符串转换为浮点数。 Here是一个链接，如果你想阅读它

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

//counters
int i = 0;
int j = 0;
int k = 0;

char c = 0; //for storing a char at a time

char result_char_array[4] = {0}; //float is a 32 bit number, so 4 bytes

FILE *filep; //pointer to file structure

float results[100] = {0}; //to store the float

int main(void)
{

    filep = fopen("C:/Documents/test.csv", "r");      //open file , read only
    if (!filep)
    {
        fprintf (stderr, "failed to open file for reading\n");
        return -1; //return negative number so you know something went wrong
    }

    c = fgetc(filep); //get first character

    while(c != EOF)
    {
        if((c == ',') || (c == '\n')) //we want to stop at each comma or newline
        {
            //i = 0; //reset the count
            results[j] = atof(result_char_array); //this converts a string to a float
            j++; //increment j
            memset(&result_char_array, 0, sizeof(result_char_array)); //clear the array
        }
        else
        {
            strncat(&result_char_array, &c, 1);
        }


        c = fgetc(filep); //get next character
        i++;
    }

    results[j] = atof(result_char_array); //convert last number

    fclose (filep); //always close the file

    for(k = 0; k <= j; k++)
    {
        printf("Number %d is: %f\n",k, results[k]); //loop through the results and print line by line
    }
    getchar();
    return 1;
}

在c中将浮点csv转换为2d数组

2 个答案: