根据输入提取字符串的特定部分

时间:2016-09-28 17:35:35

标签: python json string python-2.7 wunderground

我有一个非常大的.json转换为string,其中包含多个城市/国家/地区。

我想根据用户选择的国家/地区提取城市信息(伦敦只是一个例子)。

例如,如果用户输入的Country 为:UK,则会从字符串中提取以下信息:

由于我的经验不足,我不太确定如何实现这一目标,但我知道这需要if声明。到目前为止我的进展:

Country = raw_input('Country: ')
if 'UK' in string:
    ???

3 个答案:

答案 0 :(得分:1)

最初的反应并不是很好,因为我们中的一些人忽略了原始的JSON。但是, 提供了它,以便将来更好地表明您展示的代码段有更完整(和有效)的对应部分。

那就是说,我会将数据加载到字典中并执行以下操作:

if (element.equals("air")) {
    System.out.println("the time is " + time1);
} else if (element.equals("water"))
    System.out.println("the time is " + time2);
else if (element.equals("steel"))
    System.out.println(time3);

编辑: 根据注释使用URL而不是JSON字符串。

import json

json_string = """{
  "response": {
  "version":"0.1",
  "termsofService":"http://www.wunderground.com/weather/api/d/terms.html",
  "features": {
  "conditions": 1
  }
        , "results": [
        {
        "name": "London",
        "city": "London",
        "state": "AR",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "72847.1.99999",
        "l": "/q/zmw:72847.1.99999"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "KY",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "40741.1.99999",
        "l": "/q/zmw:40741.1.99999"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "MN",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "56036.3.99999",
        "l": "/q/zmw:56036.3.99999"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "OH",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "43140.1.99999",
        "l": "/q/zmw:43140.1.99999"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "ON",
        "country": "CA",
        "country_iso3166":"CA",
        "country_name":"Canada",
        "zmw": "00000.1.71623",
        "l": "/q/zmw:00000.1.71623"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "TX",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "76854.1.99999",
        "l": "/q/zmw:76854.1.99999"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "",
        "country": "UK",
        "country_iso3166":"GB",
        "country_name":"United Kingdom",
        "zmw": "00000.1.03772",
        "l": "/q/zmw:00000.1.03772"
        }
        ,
        {
        "name": "London",
        "city": "London",
        "state": "WV",
        "country": "US",
        "country_iso3166":"US",
        "country_name":"USA",
        "zmw": "25126.1.99999",
        "l": "/q/zmw:25126.1.99999"
        }
        ]
    }
}"""

json_object = json.loads(json_string)

world_dict = {}
for item in json_object['response']['results']:
    item_country = item['country']
    in_dict = world_dict.get(item_country)
    if in_dict:
        world_dict[item_country].extend([item])
    else:
        world_dict[item_country] = [item]

country = raw_input('Country: ')

response = world_dict.get(country)
if response:
    for item in response:
        print item
else:
    print "Not a valid country"

答案 1 :(得分:0)

import json

country = raw_input('Country: ')

jsondata = "the large json string mentioned in your post"

info = json.loads(jsondata)

for item in info:
    if item['country'] == country:
        print item

答案 2 :(得分:0)

你可以试试这个。可能仍然要考虑代码中的一些用户输入错误。例如,str.strip()和大写敏感。

import json
input_country = raw_input('Please enter country:')
with open('London.json') as fp:
    london_json = fp.read()
    london = json.loads(london_json)
    for item in london["response"]["results"]:
        if item['country'] == input_country:
            print json.dumps(item, indent = 2)