我正在使用下面使用沙丁鱼的java类,我只在目录中获取资源或zip文件列表,我应该用什么来下载zip文件?
package com.download;
import java.util.List;
import org.mule.api.MuleEventContext;
import org.mule.api.lifecycle.Callable;
import com.github.sardine.DavResource;
import com.github.sardine.Sardine;
import com.github.sardine.SardineFactory;
public class filesdownload implements Callable{
@Override
public Object onCall(MuleEventContext eventContext) throws Exception {
Sardine sardine = SardineFactory.begin("***","***");
List<DavResource> resources = sardine.list("http://hfus.com/vsd");
for (DavResource res : resources)
{
System.out.println(res);
}
return sardine;
}
答案 0 :(得分:0)
您需要使用sardine.get()
方法。 Method documentation
别忘了使用文件的绝对路径。例如:http://hfus.com/vsd/file.zip
。
代码示例:
package com.download;
import java.util.List;
import org.mule.api.MuleEventContext;
import org.mule.api.lifecycle.Callable;
import com.github.sardine.DavResource;
import com.github.sardine.Sardine;
import com.github.sardine.SardineFactory;
//TODO: add missing imports
public class filesdownload implements Callable{
@Override
public Object onCall(MuleEventContext eventContext) throws Exception {
Sardine sardine = SardineFactory.begin("***","***");
List<DavResource> resources = sardine.list(serverUrl()+"/vsd");
for (DavResource res : resources) {
if(res.getName().endsWith(".zip")) {
downloadFile(res);
}
}
return sardine;
}
private void downloadFile(DavResource resource) {
try {
InputStream in = sardine.get(serverUrl()+resource.getPath());
// TODO: handle same file name in subdirectories
OutputStream out = new FileOutputStream(resource.getName());
IOUtils.copy(in, out);
in.close();
out.close();
} catch(IOException ex) {
// TODO: handle exception
}
}
private String serverUrl() {
return "http://hfus.com";
}
}