我正在尝试将javascript中的2个数组合并为一个。
var lines = new Array("a","b","c");
lines = new Array("d","e","f");
这是一个快速示例,我希望能够将它们组合起来,以便在读取第二行时,数组中的第4个元素将返回“d”
我该怎么做?
答案 0 :(得分:273)
var a = ['a','b','c'];
var b = ['d','e','f'];
var c = a.concat(b); //c is now an an array with: ['a','b','c','d','e','f']
console.log( c[3] ); //c[3] will be 'd'
答案 1 :(得分:0)
使用现代 JavaScript:
const a = ['a', 'b', 'c'];
const b = ['d', 'e', 'f'];
const c = [...a, ...b]; // c = ['a', 'b', 'c', 'd', 'e', 'f']
答案 2 :(得分:-1)
使用本地 nodejs v16.4 进行速度测试。
对象传播速度提高 3 倍。
ObjectCombining.js
export const ObjectCombining1 = (existingArray, arrayToAdd) => {
const newArray = existingArray.concat(arrayToAdd);
return newArray;
};
export const ObjectCombining2 = (existingArray, arrayToAdd) => {
const newArray = [ ...existingArray, ...arrayToAdd ]
return newArray
};
ObjectCombining.SpeedTest.js
import Benchmark from 'benchmark';
import * as methods from './ObjectCombining.js';
let suite = new Benchmark.Suite();
const existingArray = ['a', 'b', 'c'];
const arrayToAdd = ['d', 'e', 'f'];
Object.entries(methods).forEach(([name, method]) => {
suite = suite.add(name, () => method(existingArray, arrayToAdd));
console.log(name, '\n', method(existingArray, arrayToAdd),'\n');
});
suite
.on('cycle', (event) => {
console.log(`? ${event.target}`);
})
.on('complete', function () {
console.log(`\n? ${this.filter('fastest').map('name')} is fastest.\n`);
})
.run({ async: false });