Question

我收到了一个日志文件（见下文），我需要使用bash脚本将其设置为这种格式：


title   pdfspool date  rip date   bmpspool date  CLAB date
Sometitle12  10/09/23 00:56:40 10/9/23 0:56:46  10/9/23 0:56:50  10/9/23 1:01:13

日志文件


!!Begin    
Source aserver:pdf_spool:the, Job 844b015e0043469e, Inst 844b015e0043469e    
Title Sometitle12.pdf    
Action Started Received, Ok Date 10/09/23 00:56:40    
For Administrator    
(8) DataType = PDF    
(17) Source = srv01:aserver:file_input:0    
!!End    
!!Begin    
Source aserver:rip:rip1, Job 844b015e0043469e, Inst 844b015e004346a0    
Title Sometitle12.pdf Cyan 1    
Action Started Transmit, Ok Date 10/09/23 00:56:46    
For Administrator    
(8) DataType = Bitmap    
(1) Destination = srv01:bserver:bmp_spool:the    
(4) Parent = 844b015e0043469e/844b015e0043469e    
!!End    
!!Begin    
Source bserver:bmp_spool:the, Job 844b015e0043469e, Inst 844b015e004346a0    
Title Sometitle12.pdf Cyan 1    
Action Started Received, Ok Date 10/09/23 00:56:50    
For Administrator    
(8) DataType = Bitmap    
(17) Source = srv01:aserver:rip:rip1    
!!End    
!!Begin    
Source bserver:bmp_spool:the, Job 844b015e0043469e, Inst 844b015e004346a0    
Title Sometitle12.pdf Cyan 1    
Action Atomic Accepted, Ok Date 10/09/23 01:01:13    
For Administrator    
(8) DataType = Bitmap    
(2) Source Queue = ^03Newspaper ltd(MP)^Date - 24MP^Site - N^    
(5) Requested By = clab    
(15) Approval Status = Waiting Approved    
 Changed from Waiting to Approved by clab.   
!!End

欢迎提示。

谢谢！

Answer 1

使用awk。写一个状态机。当您看到/^!!Begin$/时，切换状态，记录您的数据，转储输出并在看到/^!!End$/时切换回来。

Answer 2

awk 'BEGIN{}
/Action Started Received/ && !c{ pdfspooldate=$(NF-1)$NF ;c++}
/Action Started Received/ && c{ bmppooldate=$(NF-1)$NF ;c=0}
/Action Started Transmit/{ ripdate=$(NF-1)$NF }
/title/ { title=$2}
/Action Atomic Accepted/{ clabdate=$(NF-1)$NF }
END{ print title,pdfspooldate,ripdate,clabdate }' file

Answer 3

如果使用Perl / Python / Ruby，则应该能够在一行（匹配部分）中使用正则表达式匹配。使用多行模式，其中.将与换行符匹配。我认为awk或sed应该能够以相同的方式使用正则表达式：

例如，在Ruby中：

s = <<TEXT
!!Begin
Something haha
Title Good Bad Ugly
Date 1/1/2008
!!End
!!Begin
Other info
Title Iron Man
Date 2/2/2010
TEXT

result = s.scan(/^!!Begin.*?^Title\s+([^\n]*).*?^Date\s+([^\n]*)/m)

p result

result.each do |arr|
  puts arr.join(' ')
end

输出：

$ ruby try.rb 
[["Good Bad Ugly", "1/1/2008"], ["Iron Man", "2/2/2010"]]
Good Bad Ugly 1/1/2008
Iron Man 2/2/2010

Answer 4

我将Perl与$/ = "!!End"一起使用，然后解析每个段落。

shell脚本来解析日志文件

4 个答案: