Question

我尝试检查用户输入，但它只检查第一个单词。有关如何让程序通过整个字符串检查2D列表而不是仅检查第一个单词并输出缺失的任何建议。代码如下：

my_list = [['noisey','pc','broken']['smashed','window','glass']]
search = input('Enter what is going wrong: ')


notfound = 'True'

for i in mylist[0:1]:
   while notfound == 'True':
     if search in my_list[0]:
         print('Found in Pc')
         notfound = 'False'

     elif search in my_list[1]:
         print('Found in Home.')
         notfound = 'False'

     else:

          print('missing')
          notfound = 'False'

Answer 1

这应该可以解决问题

#!/usr/bin/python3
my_list = [['noisey','pc','broken'],['smashed','window','glass']]
search = input('Enter what is going wrong: ')

for word in search.split():
    if word in my_list[0]:
        print(word,'Found in PC');
    elif word in my_list[1]:
        print(word,'Found in Home');
    else:
        print(word,"Not Found");

输出：

Enter what is going wrong: noisey pc smashed accidentally
noisey Found in PC
pc Found in PC
smashed Found in Home
accidentally Not Found

如何检查整个用户输入而不仅仅是第一个单词

1 个答案: