你可以帮助解决这个问题这是我的作业的示例脚本。我在mysql中插入数据时遇到了问题。
<?php
if(isset($_POST['submit'])) {
$name = mysql_real_escape_string($_POST['name']);
$email = mysql_real_escape_string($_POST['email']);
$contact = mysql_real_escape_string($_POST['contact']);
$room = $_POST['room'];
$adult = $_POST['adult'];
$children = $_POST['children'];
$arrival = $_POST['arrival'];
$departure = $_POST['departure'];
$date = date("Y/m/d H:i:s");
$status = "Confirmed";
$query = "INSERT INTO booking VALUES('".$name."','".$email."','".$contact."','".$room."','".$adult."','".$children."','".$arrival."','".$departure."','".$date."','".$status."')";
if(mysql_query($query)){
?>
<div class="alert alert-success" role="alert" style="text-align:center; margin-top: 200px; background-color: #fff;" >
<p>New reservation has successfully sent!</p>
</div>
<?php
header("refresh:2;url=/index.php");
}
else{
echo "ERROR: Could not able to execute $sql. ";
}
}
?>
<form class="form-horizontal" method="post" action="reserve.php">
<div class="form-group">
<label for="focusedinput" class="col-sm-2 control-label">Name</label>
<div class="col-sm-8">
<input type="text" class="form-control1" id="focusedinput" name="name" placeholder="Enter Name" autofocus="">
</div>
</div>
<div class="form-group">
<label for="focusedinput" class="col-sm-2 control-label">Email</label>
<div class="col-sm-8">
<input type="text" class="form-control1" id="focusedinput" name="email" placeholder="Enter Email Address">
</div>
</div>
<div class="form-group">
<label for="focusedinput" class="col-sm-2 control-label">Contact</label>
<div class="col-sm-8">
<input type="text" class="form-control1" id="focusedinput" name="contact" placeholder="Enter Contact Number">
</div>
</div>
<div class="form-group">
<label for="selector1" class="col-sm-2 control-label">Select Room</label>
<div class="col-sm-8">
<select name="room" id="selector1" class="form-control1">
<option value="null">Select Type of Room</option>
<optgroup label="Dorm Type">
<option value="aguila">Aguila Room</option>
<option value="rizal">Rizal Room</option>
<option value="kalabaw">Kalabaw Room</option>
</optgroup>
<optgroup label="Private Room">
<option value="sampaguita">Sampaguita Room</option>
<option value="bahay_kubo">Bahay Kubo Room</option>
<option value="tinikling">Tinikling Room</option>
<option value="kalesa">Kalesa Room</option>
</optgroup>
</select>
</div>
</div>
<div class="form-group">
<label for="focusedinput" class="col-sm-2 control-label">Adult</label>
<div class="col-sm-3">
<select name="adult" id="selector1" class="form-control1">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
</div>
<label for="focusedinput" class="col-sm-2 control-label">Children</label>
<div class="col-sm-3">
<select name="children" id="selector1" class="form-control1">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
</div>
</div>
<div class="form-group">
<label for="focusedinput" class="col-sm-2 control-label">Arrival Date</label>
<div class="col-sm-3">
<input type="text" class="form-control1 date" id="datepicker1" type="text" name="arrival" value="DD/MM/YY" onfocus="this.value = '';" onblur="if (this.value == '') {this.value = 'DD/MM/YY';}">
</div>
<label for="focusedinput" class="col-sm-2 control-label">Departure Date</label>
<div class="col-sm-3">
<input type="text" class="form-control1 date" id="datepicker1" type="text" name="departure" value="DD/MM/YY" onfocus="this.value = '';" onblur="if (this.value == '') {this.value = 'DD/MM/YY';}">
</div>
</div>
<div class="clearfix"> </div><br><br>
<div class="panel-footer">
<div class="row"><br>
<div class="col-sm-8 col-sm-offset-2">
<input type="submit" name="submit" class="btn-success btn" value="Submit">
</div>
</div>
</div>
</form>
当我点击提交按钮时，就会发生这样的事情。 TY
答案 0 :(得分：1)
注意：在PHP 5.5.0中不推荐使用mysql扩展，并在PHP 7.0.0中删除了它。相反，应该使用MySQLi或PDO_MySQL扩展。
您犯了一些错误，因此查询可能无法将数据插入phpmyadmin数据库。你所做的基本错误是在插入查询中没有连接你想要在VALUES部分中的值，而insert语句的语法就是这样。
插入语法：
INSERT INTO table_name (column1, column2, column3,...) VALUES (value1, value2, value3,...)
注意：如果列是AUTO_INCREMENT（如“id”列）或TIMESTAMP（如“reg_date”列），则不需要在SQL查询中指定; MySQL会自动添加值。
使用以下
替换插入代码$query = "INSERT INTO booking(`name`,`email`,`contact`,`room`,`adult`,`children`,`arrival`,`departure`,`date`,`status`) VALUES('".$name."','".$email."','".$contact."','".$room."','".$adult."','".$children."','".$arrival."','".$departure."','".$date."','".$status."')";
确保我在表格中提供的所有值（column1，column2）都符合您的表结构。
Mysql连接
您在所提供的代码中缺少mysql连接代码。 确保已将连接代码放入文件中。
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_select_db( 'TUTORIALS' );
mysql_close($conn);
?>
注意：您首先将echo放入Insert语句，然后通过放置退出来中断执行;然后复制回显的语句并将其放在DB的SQL中，然后检查插入中是否发生错误。如果没有错误发生，请删除echo并删除退出;
在完成所有检查之后，我建议你查看我在上面提到的注意事项，因为它会为你提供完美的错误。
答案 1 :(得分：1)
它没有在代码中查找任何错误，请检查您的数据库表结构有关每个字段，如果您不确定那么请添加列名也像INSERT INTO table_name（column1，column2）VALUES（value1，value2）， 您可能在数据库表中有更多/更多列，请仔细检查。
答案 2 :(得分：0)
首先，您需要检查条件是否为真意味着检查控件是否在您的条件if(isset($_POST['submit'])){ //code}中放置die('inside condition')进行检查。
然后你应该插入INSERT INTO table_name (column1, column2, column3,...) VALUES (value1, value2, value3,...)
在mysql_query之后，您应该为获取错误编写echo mysql_errno() . ": " . mysql_error() . "\n";并找出执行期间发生的错误。
答案 3 :(得分：0)
mysql_ *已弃用尝试使用mysqli_ *或PDO
警告mysql_query，mysql_fetch_array，mysql_connect等..扩展在PHP 5.5.0中已弃用，并且已在PHP 7.0.0中删除。 相反，应该使用MySQLi或PDO_MySQL扩展。
//db connection
global $conn;
$servername = "localhost"; //host name
$username = "username"; //username
$password = "password"; //password
$mysql_database = "dbname"; //database name
//mysqli prepared statement
$conn = mysqli_connect($servername, $username, $password) or die("Connection failed: " . mysqli_connect_error());
mysqli_select_db($conn,$mysql_database) or die("Opps some thing went wrong");
if(isset($_POST['submit'])) {
$name = mysql_real_escape_string($_POST['name']);
$email = mysql_real_escape_string($_POST['email']);
$contact = mysql_real_escape_string($_POST['contact']);
$room = $_POST['room'];
$adult = $_POST['adult'];
$children = $_POST['children'];
$arrival = $_POST['arrival'];
$departure = $_POST['departure'];
$date = date("Y/m/d H:i:s");
$status = "Confirmed";
$stmt = $conn->prepare("INSERT INTO booking (`name`,`email`,`contact`,`room`,`adult`,`children`,`arrival`,`departure`,`date`,`status`) VALUES(?,?,?,?,?,?,?,?,?,?)");
$stmt->bind_param('ssssssssss',$name,$email,$contact,$room,$adult,$children,$arrival,$departure,$date,$status);
//The argument may be one of four types:
//i - integer
//d - double
//s - string
//b - BLOB
//change it by respectively
$stmt->execute();
$row_count= $stmt->affected_rows;
$stmt->close();
$conn->close();
if($row_count>0){
?>
<div class="alert alert-success" role="alert" style="text-align:center; margin-top: 200px; background-color: #fff;" >
<p>New reservation has successfully sent!</p>
</div>
<?php
header("refresh:2;url=/index.php");
}
else{
echo "ERROR: Could not able to execute $sql. ";
}
}
?>