Question

class A(object):
      a = 1
      b = 0
      c = None
      d = None
a_obj=A()
a_list = ['a', 'b', 'c', 'd']
attrs_present = filter(lambda x: getattr(a_obj, x), a_list)

我想要a和b属性，这里0是有效值。我不想使用比较== 0

有没有办法获得这些？任何帮助都会得到满足，谢谢。

Answer 1

如果您要排除c，d（None s），请使用is None或is not None：

attrs_present = filter(lambda x: getattr(a_obj, x, None) is not None, a_list)
# NOTE: Added the third argument `None`
#       to prevent `AttributeError` in case of missing attribute 
#       (for example, a_list = ['a', 'e'])

如果您想加入c，d，请使用hasattr：

attrs_present = filter(lambda x: hasattr(a_obj, x), a_list)

获取属性python

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