Question

我创建了以下内容：

import java.util.*;

public class morse5 {

public static void main(String [] args)
{     

  //Declare Variables
  String [][] myIndexAlphaMorse = {{"a", ".-"}, {"b", "-..."}, {"c", "-.-."}, {"d", "-.."}, {"e", "."}, {"f", "..-."}, {"g", "--."}, {"h", "...."}, {"i", ".."}, {"j", ".---"}, {"k", "-.-"}, {"l", ".-.."}, {"m", "--"}, {"n", "-."}, {"o", "---"}, {"p", ".--."}, {"q", "--.-"}, {"r", ".-."}, {"s", "..."}, {"t", "-"}, {"u", "..-"}, {"v", "...-"}, {"w", ".--"}, {"x", "-..-"}, {"y", "-.--"}, {"z", "--.."}, {"1", ".----"}, {"2", "..---"}, {"3", "...--"}, {"4", "....-"}, {"5", "....."}, {"6", "-...."}, {"7", "--..."}, {"8", "---.."}, {"9", "----."}, {"0", "-----"}, {" ", "|"}}; 


  //Test
  System.out.println(Arrays.deepToString(myIndexAlphaMorse));
  System.out.println(myIndexAlphaMorse[8][0]);


}

我想知道的是如何根据用户输入获取相应位置的值。我正在学习，所以我只想知道如何在.-输入"a"时获取UIImageView。

Answer 1

只需遍历您的数组，并将每个位置的第0个元素与您要查找的字符进行比较。

String input = "v";
String result= "";
for(int i = 0; i < myIndexAlphaMorse.length; i++){
    if(myIndexAlphaMorse[i][0].equals(input)){
        result = myIndexAlphaMorse[i][1];
        break;
   }
}
System.out.println("morse for " + input + " = " + result);

但正如另一个答案所说，你应该使用一个适合这项任务的地图。

Answer 2

对于此问题，您应该考虑使用Map而不是二维数组：

Map<String, String> myIndexAlphaMap = new HashMap<>();
myIndexAlphaMap.put("a", ".-");
myIndexAlphaMap.put("b", "-...");
// etc.

// given user input of "a" you can access via
myIndexAlphaMap.get("a");

Answer 3

或字符串数组的地图

Map<String, String[]> myIndexAlphaMap = new HashMap<String, String[]>();
myIndexAlphaMap.put("a", new String {".","-"});
myIndexAlphaMap.put("b", new String {"-",".","."});

// given user input of "a" you can access via
myIndexAlphaMap.get("a")[0];

Answer 4

您也可以使用Hash表，因为他们已经在HashMap / Map上面给出了示例：

Hashtable<String, String> table = new Hashtable<String, String>();
table.put("a", ".-");
table.put("b", "-...");

与HashMaps不同，它也是同步和线程安全的，虽然对于更大的数据集来说，它的速度更慢。

Answer 5

首先，您必须将该字母作为String对象读取。然后你可以遍历你的数组，当我们找到我们正在寻找的东西时 - 只需打印它并打破循环：

Scanner scanner = new Scanner(new InputStreamReader(System.in));
String letter = scanner.next();
for (int i=0; i<myIndexAlphaMorse.length; i++)
    if (myIndexAlphaMorse[i][0].equals(letter)){
        System.out.println(myIndexAlphaMorse[i][1]);
        break;
    }

初学者 - Java 2D数组

5 个答案: