Question

我按照django doc进行了民意调查。我有一个sqlite db＆＃39; nameinfodb＆＃39;。我想通过在线搜索姓氏来访问它。我将models.py设置为

class Infotable(models.Model):
    pid_text = models.CharField(max_length=200)
    lname_text = models.CharField(max_length=200)
    fname_text = models.CharField(max_length=200)
    affs_text = models.CharField(max_length=2000)
    idlist_text = models.CharField(max_length=2000)
    def __str__(self):
        return self

我将name.info.db复制到db.sqlite3所在的位置，更改了settings.py：

DATABASES = {
    'default': {
        'ENGINE': 'django.db.backends.sqlite3',
        'NAME': os.path.join(BASE_DIR, 'name.info.db'),
    }
}

然后我跑

python manage.py migrate  
python manage.py makemigrations pidb

然后我检查了我是否正确

$ python manage.py sqlmigrate pidb 0001

BEGIN;
--
-- Create model Choice
--
CREATE TABLE "pidb_choice" ("id" integer NOT NULL PRIMARY KEY AUTOINCREMENT, "choice_text" varchar(200) NOT NULL, "votes" integer NOT NULL);
--
-- Create model Question
--
CREATE TABLE "pidb_question" ("id" integer NOT NULL PRIMARY KEY AUTOINCREMENT, "question_text" varchar(200) NOT NULL, "pub_date" datetime NOT NULL);
--
-- Add field question to choice
--
ALTER TABLE "pidb_choice" RENAME TO "pidb_choice__old";
CREATE TABLE "pidb_choice" ("id" integer NOT NULL PRIMARY KEY AUTOINCREMENT, "choice_text" varchar(200) NOT NULL, "votes" integer NOT NULL, "question_id" integer NOT NULL REFERENCES "pidb_question" ("id"));
INSERT INTO "pidb_choice" ("id", "question_id", "choice_text", "votes") SELECT "id", NULL, "choice_text", "votes" FROM "pidb_choice__old";
DROP TABLE "pidb_choice__old";
CREATE INDEX "pidb_choice_7aa0f6ee" ON "pidb_choice" ("question_id");

COMMIT;

我没有看到有关新数据库的任何信息，我看到的只是示例民意调查数据。我这里做错了吗？我需要做的就是连接到name.info.db，并按姓氏访问它。谢谢！

Answer 1

你需要反过来做这件事：

python manage.py makemigrations pidb
python manage.py migrate

本教程的

See this part了解更多信息

在django中设置数据库

1 个答案: